Question

Luis is visiting a public garden that has a large, circular path. When he has walked one-quarter of the distance around the path, the magnitude of his displacement is 120 m.
What is the diameter Of the path?

Answer 1

Answer:

120√2 m is the diameter of the path.      

Step-by-step explanation:

We are given the following in the question:

When Luis has walked one-quarter of the distance around the circular path, the magnitude of his displacement is 120 m.

Displacement = 120 m

The two radius and the displacement forms a right angles triangle.

By Pythagoras theorem:

$r^2 + r^2 = (120)^2$

where r is the radius of the circular path.

$2r^2 = (120)^2\\r^2 = 7200\\r = 60\sqrt{2}~m$

Thus, diameter of circular path is

$d = 2r = 120\sqrt{2}~m$

Thus, 120√2 m is the diameter of the path.

The attached image shows the circular path.