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Aliun [14]
3 years ago
11

Can someone help me find the area

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
7 0
To find the volume of a container, you simply multiply: L(ength) x B(ase) x H(eight).

In total, you should get a volume of 1078in^3 (the bigger container) plus 175in^3 (the smaller container on top of the bigger one). The answer is 1,253in^3.

Hope this helped! :)
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Two thirds of a number decreased by six is two. what is the number?
Kisachek [45]
Answer:  The number is:  " 12 ". 

____________________________________
  Let "x" represent "the unknown number" (for which we wish to solve.

The expression:

\frac{2}{3} x  <span>− 6  =  2  ;   Solve for "x" ;  
</span>_______________________________________________
Method 1) 

   Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:

      →   \frac{2}{3} x = 8 ;
______________________________________________
Multiply each side of the equation by "\frac{3}{2}" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
______________________________________________
     → \frac{3}{2} * \frac{2}{3} x = 8 * \frac{3}{2} ;

       →  x = 8 * \frac{3}{2} ;

                = \frac{8}{1} * \frac{3}{2} ;

                = \frac{8*3}{1*2} ;
       
                = \frac{24}{2} ;
 
                = <span>1<span>2 .</span></span>
______________________________________________
  x =  12 .
______________________________________________
Method 2)
______________________________________________
\frac{2}{3} x  − 6  =  2  ;   Solve for "x" ; 

   Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:
      →   \frac{2}{3} x = 8 ;
______________________________________________
Multiply each side of the equation by "3" ; to get rid of the "fraction" ;
               → 3 * \frac{2}{3} x = 8 * 3  ;
               → \frac{3}{1} * \frac{2}{3} x = 8 * 3 ;
               → \frac{3*2}{1*3}  x = 8 * 3 
               → \frac{6}{3} x = 24 ; 

                → 2x = 24 ;

 →  Divide each side of the equation by "2" ; to isolate "x" on one side of the equation; & to solve for "x" : 
 
                    2x / 2 = 24 / 2  ;

                        x = 12 .
__________________________________________________
Method 3).
__________________________________________________
\frac{2}{3} x  − 6  =  2  ;   Solve for "x" ;  
_______________________________________________
Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:

      →   \frac{2}{3} x = 8 ;
______________________________________________
Now, divide each side of the equation by " \frac{2}{3} " ;
  to isolate "x" on one side of the equation; & to solve for "x" ;
___________________________________________________
{\frac{2}{3} x }  /  {\frac{2}{3}}  =  8 / {\frac{2}{3}} ;

to get:  x =  8 / {\frac{2}{3}} ;

                =  8 * (\frac{3}{2} ;

                =  \frac{8}{1}  *  \frac{3}{2} ;

                =  \frac{8*3}{1*2} ;

                =  \frac{24}{2} ;

                = 12 ; 
___________________________________________
                         x = 12 .
___________________________________________
NOTE:  Variant:  (in "Methods 2 & 3") :
___________________________________________
At the point where:
___________________________________________
 =  8 * (\frac{3}{2}) ;

  =  \frac{8}{1}  *  \frac{3}{2} ;
__________________________________________
  We can cancel out the "2" to a "1" ; and we can cancel out the "8" to a "4" ;
__________________________________________
  {since: "8÷2 = 4" ; and since:  "2÷2 =1" } ;
__________________________________________
and we can rewrite the expression:
__________________________________________
 \frac{8}{1}  *  \frac{3}{2} ;
__________________________________________
as:   \frac{4}{1}  *  \frac{3}{1} ; 
__________________________________________
which equals:
__________________________________________
→  \frac{4*3}{1*1} ; 

   =   \frac{12}{1} ;

            =  12 .
__________________________________________
         x = 12 . 
__________________________________________
Answer:  The number is:  " 12 ". 
__________________________________________
8 0
4 years ago
Jack needs 22 pirate for every two pirate ships he Manages
solniwko [45]

Answer:

Hi there! There is only one part of a question. I‘m not sure how to help you...

Sorry! Have a good day/night!

Step-by-step explanation:

3 0
3 years ago
What number divided by −3 gives 12 as the result?
Ronch [10]

Answer:

-36

Step-by-step explanation:

-3 ×12=--36

7 0
3 years ago
Read 2 more answers
How do I find a2 and a3 for the following geometric sequence? 54, a2, a3, 128
vlada-n [284]
The formula for the nth term of a geometric sequence:
a_n=a_1 \times r^{n-1}
a₁ - the first term, r - the common ratio

54, a_2, a_3, 128 \\ \\&#10;a_1=54 \\&#10;a_4=128 \\ \\&#10;a_n=a_1 \times r^{n-1} \\&#10;a_4=a_1 \times r^3 \\&#10;128=54 \times r^3 \\&#10;\frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\&#10;\frac{64}{27}=r^3 \\&#10;\sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\&#10;\frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\&#10;r=\frac{4}{3}

a_2=a_1 \times r= 54 \times \frac{4}{3}=18 \times 4=72 \\&#10;a_3=a_2 \times r=72 \times \frac{4}{3}=24 \times 4=96 \\ \\&#10;\boxed{a_2=72, a_3=96}
7 0
3 years ago
Read 2 more answers
Find common ratio of the sequence -8 , 24, -72, 216 ​
mafiozo [28]

Answer:

r=-3 a^n=-8(-3)^n-1

Step-by-step explanation:

8 0
3 years ago
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