Answer:
87.29%
Step-by-step explanation:
Given: Mean= 68.8 inches
Standard deviation= 2.8 inches
Now, finding the percent of the men in the sample were greater than 72 inches.
We know, z-score= 
z-score= 
⇒ z-score= 
∴ z-score= 1.14
Next, using normal distribution table to find percentage.
Coverting 0.8729 into percentage= 
We get the percentage as 87.29%
Hence, 87.29% of the men in the sample were greater than 72 inches.
Answer:
I got 15.
Step-by-step explanation:
I used a calculator and 6 / (2/5) = 15
Answer: I'd assume its B 100 miles each day.
Step-by-step explanation:
Because 70 x 100 is 7,000 which is equal to the amount of miles stared in the question
The interquartile range is 12-6=6
Answer:
-2x² - 8x + 15 = 0
Step-by-step explanation:
Given the following algebraic expression;
x² – 7x + 5
-3x² - x + 10
To add the equation together;
x² – 7x + 5 + (-3x² - x + 10) = 0
x² – 7x + 5 - 3x² - x + 10 = 0
Collecting like terms, we have;
(x² - 3x²) - (7x + x) + (5 + 10) = 0
-2x² - 8x + 15 = 0
