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alexandr1967 [171]
3 years ago
13

Megan surveyed 40 students in her grade level and asked them what their favorite vegetable was. The results are in the circle gr

aph below. Vegetables 10% 30% Carrots Tomatoes 25% Zucchini Squash Potatoes 20% 15% A. How many students said carrots were their favorite vegetable? I B. How many students said squash was their favorite vegetable?​
Mathematics
1 answer:
Mariana [72]3 years ago
8 0

Answer:

gjlll has 3

Step-by-step explanation:

amy has 555

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A square tile has a side of 12 cm. What is the area of the tile?
Jet001 [13]

Answer:

144 cm^2

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Well, we know the area of a square is L*W

L=12

W=12

12*12=144 cm^2

(っ◔◡◔)っ ♥ Hope this helped, have a great day! ♥

˜”*°•.˜”*°• ~Star •°*”˜.•°*”˜

3 0
3 years ago
Can someone please simply this and show the work ?
const2013 [10]

Answer:

it's one of this two. if it's exactly how you have written it , it's the first picture.

6 0
3 years ago
Read 2 more answers
Which of the following describe 9.49?
mylen [45]

Answer:take 9x49

Step-by-step explanation:

You’ll get the answer

8 0
3 years ago
If the seed company recommends planting approximately 350 grass seeds per square meter, about how many grass seeds will he need?
Svetach [21]

Answer:

83422.5 grass seeds

Step-by-step explanation:

Applying,

A = 1/2bh....................... Equation 1

Where A = Area of the Triangle, b = base, h = height.

But, from the diagram,

tanФ = 20/b

b = 20/tanФ.................. Equation 2

Substitute equation 2 into equation 1

A = 1/2(20/tanФ)(h)................ Equation 3

Given: h = 20 m, Ф = 40°

Substitute these values into equation 3

A = 1/2(20×20)/tan40°

A = 200/tan40°

A = 238.35 m²

If the seed company recommends planting approximately 350 grass seeds per square meter,

Therefore,

Number of grass seed need = (350×238.35)

Number of grass seed needed = 83422.5 grass seeds

3 0
3 years ago
Help! Thanks!!!!!!!!!
san4es73 [151]

1)

∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰

AB = 370 m

AC = 510 m

To find BC we can use cosine law.

a² = b² + c² -2bc*cos A

|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)

|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =

|BC| ≈ 553 m


2)

To find ∠ACB, we are going to use law of sine.

sin(∠BAC)/|BC| = sin(∠ACB)/|AB|

sin(76⁰)/553 m = sin(∠ACB)/370 m

sin(∠ACB)=(370*sin(76⁰))/553 =0.6492

∠ACB = 40.48⁰≈ 40⁰


3)

∠BAC = 76⁰

∠ACB = 40⁰

∠CBA = 180-(76+40) = 64⁰


Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰


4)

Shortest distance from A to BC is height (h) from A to BC.


We know that area of the triangle

A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).

Also, area the same triangle

A= (1/2)|BC|*h = (1/2)*553*h.


So, we can write

(1/2)*370*510*sin(76⁰) =(1/2)*553*h

370*510*sin(76⁰) =553*h

h= 370*510*sin(76⁰) / 553= 331 m

h=331 m


4 0
3 years ago
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