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givi [52]
3 years ago
9

Dustin complained 3/8 of a homework assignment that has 24 problems. Kelsey completed 4/15 of a homework assignment that has 30

problems. Who has completed more problems?
Mathematics
1 answer:
hjlf3 years ago
3 0

Dustin has completed more problems.

You can first use the 2 factors of 24, which are 3 and 8. To make it so you can compare the amount of problems completed with total amount, you need to multiple 8 x 3 and 3 x 3. This will turn 3/8 into 9/24, meaning that dustin has completed 9 problems. You can first use the 2 factors of 30, which are 2 and 15. Once again, to make it so you can compare the amount of problems completed with total amount, you need to multiple 2 x 15 and 2 x 4. This will turn 4/15 into 8/30, meaning that kelsey has completed 8 problems.

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Step-by-step explanation:

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2 years ago
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Answer:   a) \bold{\dfrac{3}{16}}     b) \bold{\dfrac{1}{36}}

<u>Step-by-step explanation:</u>

a) In order to get an even number, you have the 3 different scenarios:

1) Even, Even, Even, Even     \dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}

2) Even, Even, Odd, Odd   \dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}

3) Odd, Odd, Odd, Odd   \dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}

<em>Order doesn't matter</em>

Add them up to get your answer: \dfrac{1}{16}+\dfrac{1}{16}+\dfrac{1}{16}\quad =\large\boxed{\dfrac{3}{16}}

b) If one die is a 2 and another is a 3 and the other two dice can be any number, then you have 1 possibility for a 2, 1 possibility for a 3, and 6 possibilities for each of the other two dice.

\dfrac{1\times 1\times 6\times 6}{6^4}\quad =\dfrac{1}{6^2}\quad =\large\boxed{\dfrac{1}{36}}

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The equation is 12(10)=120ft

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2 years ago
HELP FAST PLEASE
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B    18 and 24

6x3=18

8x3=24

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