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kirill [66]
3 years ago
12

Suppose that F(x) = x^2 and G(x) = 2x^2-5. Which statement best compares the graph G(x) with the graph of F(x)?

Mathematics
2 answers:
notsponge [240]3 years ago
8 0
I believe the correct answer from the choices listed above is option  D. The graph <span>G(x) as compared to the graph of F(x) would be that the </span><span>graph of G(x) is the graph of F(x) stretched vertically and shifted 5 units down. 2 is a stretch factor and -5 is the shift downwards of the graph. Hope this answers the question.</span>
Trava [24]3 years ago
4 0

Answer:

D.The graph G(x) is the graph of F(x) stretched vertically and shifted 5 units down.

Step-by-step explanation:

We are given that

F(x)=x^2

G(x)=2x^2-5

We have to find that which statement compares best the graph G(x) with graph of F(x).

Graph of F(x) is the graph of parabola along y- axis with vertex (0,0).

Graph stretched vertically 'a' times by the formula y'=ay

Now, the graph F(x) is stretched vertically  2 times initial graph then

F'(x)=2x^2

Now , shift the graph 5 units down then we get

G(x)=2x^2-5

The general equation of parabola along y- axis is given by

y=(x-h)^2+k

Where (h,k)=Vertex

Compare the graph G(x) with the general equation of parabola then , we get h=0, k=-5

Therefore, vertex of G(x) is at (0,-5).

Hence, the graph G(x) is the graph of F(x) stretched vertically and shifted 5 units down.

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Problem:<br><br> 3 divided 5= 3/5<br><br> ——— x ——— = ———
grin007 [14]

Answer:

3=1/5

Step-by-step explanation:

hope this helps :) have a nice day :)

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B12x-7%3D0%20%5C%5C" id="TexFormula1" title="2x^{2} +12x-7=0 \\" alt="2x^{2}
m_a_m_a [10]

Answer:

-2. 46

- 9.54

Step-by-step explanation:

  • 2x²+12x-7=0
  • 2x²+12x+18= 25
  • 2*(x²+6x+9)=25
  • 2*(x+6)²= 5²
  • x+6= 5√2/2 ⇒ x= 5√2/2 -6 ≈ -2. 46
  • x+6= -5√2/2 ⇒ x= -5√2/2 -6 ≈ - 9.54
4 0
3 years ago
What two numbers multiply to 54 and add up to 7
k0ka [10]
Xy = 54
x + y = 7

xy = 54
\frac{xy}{x} = \frac{54}{x}
y = \frac{54}{x}

x + y = 7
x + \frac{54}{x} = 7
\frac{x^{2}}{x} + \frac{54}{x} = 7
\frac{x^{2} + 54}{x} = 7
x^{2} + 54 = 7x
x^{2} - 7x + 54 = 0
x = \frac{-(-7) \± \sqrt{(-7)^{2} - 4(1)(54)}}{2(1)}
x = \frac{7 \± \sqrt{49 - 216}}{2}
x = \frac{7 \± \sqrt{-167}}{2}
x = \frac{7 \± i\sqrt{167}}{2}
x = \frac{7 \± 12.9i}{2}
x = 3.5 \± 6.45i
x = 3.5 + 6.45i    or    3.5 - 6.45i

                  x + y = 7
   3.5 + 6.45i + y = 7
- (3.5 + 6.45i)       - (3.5 + 6.45i)
                        y = 3.5 - 6.45i
                  (x, y) = (3.5 + 6.45i, (3.5 - 6.45i)

                          or

                  x + y = 7
   3.5 - 6.45i + y = 7
- (3.5 - 6.45i)     - (3.5 - 6.45i)
                       y = 3.5 + 6.45i
                 (x, y) = (3.5 - 6.45i, 3.5 + 6.45i)

The two numbers that add up to 7 and can multiply to 54 is 3.5 ± 6.45i.
5 0
3 years ago
When you use a transversal to construct a line parallel to a given line, how do you prove that the lines are parallel?
DedPeter [7]
Parallel lines never touch each other.
4 0
3 years ago
What is the value of the expression |-5x+12| when x=5
MissTica

First, plug in 5 for x:

| -5 * 5 + 12 | = |-25 + 12| = |-13|

Those two lines are absolute value, which measures the distance from the number to 0 on a number line. This distance is always positive.

The distance from -13 to 0 on a number line is 13. The answer is 13.

6 0
4 years ago
Read 2 more answers
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