What is the length of segment AB to the nearest tenth?
1 answer:
Answer:
4.9 units
Step-by-step explanation:
Distance between 2 points= sqrt [(x-x)^2 + (y-y)^2
A= -4,2) and B= (1,4)
d = sqrt[(-4-1)^2 + (2-4)^2]
= sqrt (25+4)
= sqrt29
= 4.9 units
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