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Sedbober [7]
3 years ago
12

What is the length of segment AB to the nearest tenth?

Mathematics
1 answer:
ankoles [38]3 years ago
7 0

Answer:

4.9 units

Step-by-step explanation:

Distance between 2 points= sqrt [(x-x)^2 + (y-y)^2

A= -4,2) and B= (1,4)

d = sqrt[(-4-1)^2 + (2-4)^2]

= sqrt (25+4)

= sqrt29

= 4.9 units

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Help, i know the answer but i don’t know how to do the work
Diano4ka-milaya [45]

Answer:

C

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying each radical before combining them.

\sqrt{45t}

= \sqrt{9(5t)}

= \sqrt{9} × \sqrt{5t} = 3\sqrt{5t}

-----------------------------------------------------------------------------

\sqrt{125t}

= \sqrt{25(5t)}

= \sqrt{25} × \sqrt{5t} = 5\sqrt{5t}

---------------------------------------------------------------------------

Hence

2(3\sqrt{5t}) - 3(5\sqrt{5t}

= 6\sqrt{5t} - 15\sqrt{5t}

= - 9\sqrt{5t} → C

7 0
4 years ago
On day t=0t=0t, equals, 0, the stock is at its average value of {\$}3.47$3.47dollar sign, 3, point, 47 per share, but 91.2591.25
Norma-Jean [14]

Answer:

S(t) = a.sin (b.t) + d

a = -1.5, b = (2π/365), d = 3.47

S(t) = -1.5 sin (2πt/365) + 3.47

Step-by-step explanation:

Complete Question is presented in the attached image to this solution.

- Dingane has been observing a certain stock for the last few years and he sees that it can be modeled as a function S(t) of time t (in days) using a sinusoidal expression of the form

S(t) = a.sin(b.t) + d.

On day t = 0, the stock is at its average value of $3.47 per share, but 91.25 days later, its value is down to its minimum of $1.97.

Find S(t). t should be in radians.

S(t) =

Solution

S(t) = a.sin(b.t) + d.

At t = 0, S(t) = $3.47

S(0) = a.sin(b×0) + d = a.sin 0 + d = 3.47

Sin 0 = 0,

S(t=0) = d = 3.47.

At t = 91.25 days, S(t) = $1.97

But, it is given that T has to be in radians, for t to be in radians, the constant b has to convert t in days to radians.

Hence, b = (2π/365)

S(91.25) = 1.97 = a.sin(b×91.25) + d

d = 3.47 from the first expression

S(t = 91.25) = a.sin (91.25b) + 3.47 = 1.97

1.97 = a.sin (2π×91.25/365) + 3.47

1.97 = a sin (0.5π) + 3.47

Sin 0.5π = 1

1.97 = a + 3.47

a = -1.5

Hence,

S(t) = a.sin (b.t) + d

a = -1.5, b = (2π/365), d = 3.47

S(t) = -1.5 sin (2πt/365) + 3.47

Hope this Helps!!!

6 0
3 years ago
mrs marvel bought some t-shirts. she gave 1/2 of them to coach nine, 2 of them to mrs. lewis and kept 5 to herself. how many t-s
vesna_86 [32]

Answer:

14

Step-by-step explanation:

assuming that the shirts in the question are the only shirts bought, 2+5 is 7, and the other half would also be 7, making it 14

8 0
3 years ago
Write the sum using summation notation, assuming the suggested pattern continues.
Usimov [2.4K]

Answer:

Sum of the sequence will be 648

Step-by-step explanation:

The given sequence is representing an arithmetic sequence.

Because every successive term of the sequence is having a common difference d = -3 - (-9) = -3 + 9 = 6

3 - (-3) = 3 + 3 = 6

Since last term of the sequence is 81

Therefore, by the explicit formula of an arithmetic sequence we can find the number of terms of this sequence

T_{n}=a+(n-1)d

where a = first term of the sequence

d = common difference

n = number of terms

81 = -9 + 6(n - 1)

81 + 9 = 6(n - 1)

n - 1 = \frac{90}{6}=15

n = 15 + 1 = 16

Now we know sum of an arithmetic sequence is represented by

\sum_{n=1}^{n}(a_{n})=\frac{n}{2}(a_{1}+a_{n})

Now we have to find the sum of the given sequence

S_{16}=\frac{16}{2}[-9 + (16-1)6]

              = 8[-9 + 90]

              = 8×81

              = 648

Therefore, sum of the terms of the given sequence will be 648.

6 0
3 years ago
3+1 + - + ... ?<br> What is the sum of the first 7 terms of this geometric series: 3+1+ 3
mote1985 [20]

Answer:

15

Step-by-step explanation:

3+1+3+1+3+1+3= 15 this is what it would look like if you write it out. To save time do 3 times 4 to get 12 and then just add three ones to 12 to get 15.

8 0
3 years ago
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