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3 years ago

What is the length of segment AB to the nearest tenth?

Mathematics

1 answer:

ankoles [38]3 years ago

7 0

Answer:

4.9 units

Step-by-step explanation:

Distance between 2 points= sqrt [(x-x)^2 + (y-y)^2

A= -4,2) and B= (1,4)

d = sqrt[(-4-1)^2 + (2-4)^2]

= sqrt (25+4)

= sqrt29

= 4.9 units

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balu736 [363]

Answer:

slope = 1

Step-by-step explanation:

-3 | -3

5 | 5

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8 | 8

8/8= 1

7 0

3 years ago

I need help please can someone help me find each area thank you

nikitadnepr [17]

Answer:

it is easy use the formula of triangle which is 1/2(base × height) and base is the side where the height touches and height means the perpendicular line.

And in some cases there may be the use of pythagoras theorem

8 0

3 years ago

Read 2 more answers

Points scored in a basketball game vary directly with shots taken. If a player scores 50 points and takes 40

KATRIN_1 [288]

Answer:

She would have scored 75 points.

Step-by-step explanation:

Points scored in a basketball game vary directly with shots taken.

This means that this question can be solved by proportions, using a rule of three.

How many would she have scored if she takes 60 shots?

Using a rule of three:

50 points - 40 shots

x points - 60 shots

Applying cross multiplication:

$40x = 50*60$

Dividing both sides by 40

$x = 50*1.5 = 75$

She would have scored 75 points.

6 0

3 years ago

Explain how to find the vertex of 2x^2+12x+16

Elina [12.6K]

The vertex form:

$y=a(x-h)^2+k\\\\(h,\ k)-vertex$

Use $(a+b)^2=a^2+2ab+b^2\qquad(*)$

$2x^2+12x+16=2(x^2+6x)+16=2(x^2+2(x)(3))+16\\\\=2(\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2)+16=2((x+3)^2-9)+16\\\\=2(x+3)^2+(2)(-9)+16=2(x+3)^2-18+16\\\\=\boxed{2(x-(-3))^2-2}\to h=-3,\ k=-2$