Answer:
Solution : ( - 8, - 5π/3 )
Step-by-step explanation:
There are four cases to consider here, the first two with respect to r > 0, the second two with respect to r < 0. For r < 0 we have the coordinates ( - 8, 60° ) and ( - 8, - 300° )
. - 300° in radians is - 5π/3, and hence our solution is option d. But let me expand on how to receive the coordinates. Again r is the directed distance from the pole, and theta is the directed angle from the positive x - axis.
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So when r is either negative or positive, we can tell that this point is 8 units from the pole. Therefore - r = - 8 in both our second cases ( we are skipping the first two cases for simplicity ). For r < 0 the point will lay on the ray pointing in the opposite direction of the terminal side of theta.
Our first coordinate is ( - 8, 60° ). Theta will be 2 / 3rd of 90 degrees, or 60 degrees, for - r. Respectively the remaining degrees will be negative, 360 - 60 = 300, - 300. Our second point for - r will thus be ( - 8, - 300° )
. - 300° = - 5π/3 radians, and our coordinate will be ( - 8, - 5π/3 ).
Answer:
5
Step-by-step explanation:
We cannot repeat an x value for the relation to be a function
Since x=3 ,4, 7 are already used
We must let x=5
Since
the domain of f(x) is the set of non-negative integers, because we can't feed a square root with negative inputs. So, you couldn't comput f(-9)
Unless you're allowed to use complex numbers, in that case we have
Which evaluates to
Answer:
bc=3
Step-by-step explanation:
c=3b
times be on both sides to eliminate it on the side with the 3.
F(3) occurs when x =3. So lets plug 3 into our equation.
F(3) = -28
I hope this helps! :)
