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Musya8 [376]
3 years ago
10

What is the period of cos (x/3

Mathematics
1 answer:
slava [35]3 years ago
7 0

Answer:

What is the period of COSX?

The period of a periodic function is the interval of x-values on which the cycle of the graph that's repeated in both directions lies. Therefore, in the case of the basic cosine function, f(x) = cos(x), the period is 2π.

Step-by-step explanation:

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A survey shows that the probability that an employee gets placed in a suitable job is 0.65. A psychometric test consultant claim
fgiga [73]

Answer:

A survey shows that the probability that an employee gets placed in a suitable job is 0.65.

So, the probability he is in the wrong job is 0.35.

The test has an accuracy rate of 70%.

So, the probability that the test is inaccurate is 0.3. 

Thus, the probability that someone is in the right job and the test predicts it wrong is 0.65\times0.3=0.195

The probability that someone is in the wrong job and the test is right is 0.35\times0.7=0.245

6 0
3 years ago
State the degree and dominant term of this polynomial
artcher [175]

The degree of the polynomial f(x) = 2x(x - 3)³(x + 1)(4x - 2) is 6, and the dominant term is - 216x²

<h3>The degree of the polynomial?</h3>

The polynomial function is given as:

f(x) = 2x(x - 3)³(x + 1)(4x - 2)

To determine the degree, we simply add the multiplicities.

So, we have:

Degree = 1 + 3 + 1 + 1

Evaluate

Degree = 6

Hence, the degree of the polynomial is 6

<h3>The dominant term of the polynomial</h3>

We have:

f(x) = 2x(x - 3)³(x + 1)(4x - 2)

Expand

f(x) = 8x⁶ - 68x⁵ + 176x⁴ - 72x³ - 216x² + 108x

The term with the highest absolute value is - 216x²

Hence, the dominant term is - 216x²

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

4 0
2 years ago
Order from least to greatest 4.5 3.9 4.258 3.75 4.256
djyliett [7]
3.75, 3.9, 4.256, 4.258, 4.5
7 0
3 years ago
Read 2 more answers
Someone help me please
Novosadov [1.4K]
\begin{gathered} T=\text{ 2}\pi\sqrt[\placeholder{⬚}]{\frac{L}{9.8}} \\ 4.5=\text{ 2}\pi\sqrt[\placeholder{⬚}]{\frac{L}{9.8}} \\ \frac{4.5}{2\pi}=\text{ }\sqrt[]{\frac{L}{9.8}} \\ 0.7162=\text{ }\sqrt[]{\frac{L}{9.8}} \\ (0.7162)^2=\frac{L}{9.8} \\ 0.513(9.8)=L \\ 5.027=L \\ L\approx5.0m \end{gathered}

Approximately 5 meters long.

7 0
1 year ago
Analyze the end behavior of each function below. Then, choose one of the functions, and explain how you determined
kumpel [21]

Answer:

End behavior of a polynomial function depended on the degree and its leading coefficient.

1. If degree is even and leading coefficient is positive then

p(x)\rightarrow \infty\text{ as }x\rightarrow \infty

p(x)\rightarrow \infty\text{ as }x\rightarrow -\infty

2. If degree is even and leading coefficient is negative then

p(x)\rightarrow -\infty\text{ as }x\rightarrow \infty

p(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty

3. If degree is odd and leading coefficient is positive then

p(x)\rightarrow \infty\text{ as }x\rightarrow \infty

p(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty

4. If degree is odd and leading coefficient is negative then

p(x)\rightarrow -\infty\text{ as }x\rightarrow \infty

p(x)\rightarrow \infty\text{ as }x\rightarrow -\infty

(a)

f(x)=x^4

Here, degree is even and leading coefficient is positive.

f(x)\rightarrow \infty\text{ as }x\rightarrow \infty

f(x)\rightarrow \infty\text{ as }x\rightarrow -\infty

(b)

g(x)=-x^4

Here, degree is even and leading coefficient is negative.

g(x)\rightarrow -\infty\text{ as }x\rightarrow \infty

g(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty

(c)

h(x)=x^3

Here, degree is odd and leading coefficient is positive.

h(x)\rightarrow \infty\text{ as }x\rightarrow \infty

h(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty

(d)

k(x)=-x^3

Here, degree is odd and leading coefficient is negative.

k(x)\rightarrow -\infty\text{ as }x\rightarrow \infty

k(x)\rightarrow \infty\text{ as }x\rightarrow -\infty

4 0
3 years ago
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