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victus00 [196]
3 years ago
9

If f(x) = x2 – 2x and g(x) = 6x + 4, for which value of x does (f + g)(x) = 0?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
7 0

Answer:

The answer is second one (-2)

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HELLPPPP LIKE ASAP PLEASE!! Each of these numbers represents the score that a student got on a set of math tests. What is the me
sleet_krkn [62]

Answer:

81.66 repeating

Step-by-step explanation:

86+72+65+82+91+94=490

490÷6=81.66 repeating

EDIT: this answer is false

6 0
3 years ago
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Each piece of candy weighs one eight pound. If Donna buys 15 pieces of candy how many pounds of candy will she buy.
likoan [24]

Answer:

120

Step-by-step explanation:

15/(1/8)

4 0
3 years ago
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I need this asap ty:p
Anastasy [175]

Answer:

(a) x = -2y

(c) 3x - 2y = 0

Step-by-step explanation:

You can tell if an equation is a direct variation equation if it can be written in the format y = kx.

Note that there is no addition and subtraction in this equation.

Let's put these equations in the form y = kx.

(a) x = -2y

  • y = x/-2 → y = -1/2x
  • This is equivalent to multiplying x by -1/2, so this is an example of direct variation.

(b) x + 2y = 12

  • 2y = 12 - x
  • y = 6 - 1/2x
  • This is not in the form y = kx since we are adding 6 to -1/2x. Therefore, this is <u>NOT</u> an example of direct variation.

(c) 3x - 2y = 0

  • -2y = -3x
  • y = 3/2x
  • This follows the format of y = kx, so it is an example of direct variation.

(d) 5x² + y = 0

  • y = -5x²
  • This is not in the form of y = kx, so it is <u>NOT</u> an example of direct variation.

(e) y = 0.3x + 1.6

  • 1.6 is being added to 0.3x, so it is <u>NOT</u> an example of direct variation.

(f) y - 2 = x

  • y = x + 2
  • 2 is being added to x, so it is <u>NOT</u> an example of direct variation.

The following equations are examples of direct variation:

  • x = -2y
  • 3x - 2y = 0
7 0
3 years ago
Read 2 more answers
Using appropriate properties find: 2/3 × 3/4 + 3/7 × 3/4​
Viktor [21]

Answer:

\frac{23}{28}

Step-by-step explanation:

\frac{2}{3}  \times  \frac{3}{4}  +  \frac{3}{7}  \times  \frac{3}{4}

=  >  \frac{3}{4} ( \frac{2}{3}  +  \frac{3}{7} )

=  >  \frac{3}{4}  \times  \frac{23}{21}

Reducing 3 from numerator and denominator,

=  >  \frac{23}{4 \times 7}  =  \frac{23}{28}

3 0
3 years ago
3х - 30 = у<br> 7y - 6 = 3х
mars1129 [50]

Answer:

Step-by-step explanation:

This one is simple substitution... at least, substitution is the easiest method. The first equation is 3<em>x</em> – 30 = <em>y</em>  and the second is 7<em>y</em> – 6 = 3<em>x</em>

As I look, I see 3 ways to use substitution to solve this:

  1. substitute 7<em>y</em> – 6 for 3<em>x</em>
  2. substitute 3<em>x</em> – 30 for <em>y</em>
  3. solve 3<em>x</em> – 30 = <em>y</em> for 3<em>x</em> and make it equal to 7<em>y</em> – 6

We're going to only use 1 method for the sake of time. Try the other two on your own. Assuming you don't make any mistakes, they will work.

<u>Method 1</u>:

3<em>x</em> – 30 = <em>y</em>

7<em>y</em> – 6 = 3<em>x</em>  — initial system of equations

7<em>y</em> – 6 – 30 = <em>y</em>  — substitute 7<em>y</em> – 6 for 3<em>x</em>

<u>7</u><u><em>y</em></u> – 6 – 30 = <u><em>y</em></u>  — marking like terms, bold for constants, <u>underlined</u> for variables

7<em>y</em> – 36 = <em>y</em>  — combining the constants and simplifying

Here, you could diverge into multiple paths: add 36 to both sides, subtract <em>y</em> from both sides, divide by 6 OR subtract 7<em>y</em> from both sides and divide by –6 . For the sake of time, I'm subtracting 7<em>y</em>, though I don't like dealing with negatives.

7<em>y</em> – 7<em>y</em> – 36 = <em>y</em> – 7<em>y</em>  — subtract 7<em>y</em> from both sides

–36 = –6<em>y</em>  — simplify

–36 ÷ –6 = –6<em>y</em> ÷ –6  — divide by –6 on both sides

<em>y</em> = 6  — simplify

Again, we can diverge here: substitute <em>y</em> into 3<em>x</em> – 30 = <em>y</em> or substitute <em>y</em> into 7<em>y</em> – 6 = 3<em>x</em>

I'm going to choose 3<em>x</em> – 30 = <em>y</em> but it will work either way, should you take the time (if you have it) to chase down every path this problem can take.

3<em>x</em> – 30 = <em>y</em>  — initial equation

3<em>x</em> – 30 = 6  — substitute 6 for <em>y</em>

3<em>x</em> – 30 + 30 = 6 + 30  — add 30 to both sides to isolate 3<em>x</em>

3<em>x</em> = 36  — simplify the expression

3<em>x</em> ÷ 3 = 36 ÷ 3  — divide both sides by 3 to isolate <em>x</em>

<em>x</em> = 12  — simplify

So, we have <em>x</em> = 12 and <em>y</em> = 6 . We know they work for 3<em>x</em> – 30 = <em>y</em>  but not if they work for 7<em>y</em> – 6 = 3<em>x</em> . Let's substitute those in to see if (12, 6) really is the solution point.

7<em>y</em> – 6 = 3<em>x</em>  — original equation

7(6) – 6 ≟ 3(12)  — substitute 6 for <em>y</em> and 12 for <em>x</em>

42 – 6 ≟ 36  — simplify by multiplying

36 = 36 ✔  — simplify by combining like terms on left side

Success! It works! We have found our solution!

I hope this helps increase your understanding of the concept. Have a great day!

8 0
3 years ago
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