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3 years ago

Olivia is cutting a 1 1/2 m by 3/4 m piece of rectangular paper into two pieces along its diagonal. Find the area

Mathematics

1 answer:

netineya [11]3 years ago

8 0

Answer:

9/16 m.

Step-by-step explanation:

When you cut two pieces along its diagonal it causes it to be two congruent triangular pieces.

You need to multiply the length and the width to find an area:

1 1/2 × 3/4

Now you need to change it into an improper fraction:

1*2+1 = 2+1 = 3; this gives us 3/2:

3/2 × 3/4 = 9/8 = 1 1/8

Dividing it by 2:

9/8 ÷ 2

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Graph the function. H(x) = 6 • (4/3)^x

Aloiza [94]

Answer:

Step-by-step explanation:

8 0

3 years ago

Parallel, perpendicular or neither

sergejj [24]

Answer:

Step-by-step explanation:

x=3 and x=-4 are parallel, vertical lines

:::::

x-y = 3, slope = 1

2x-2y = 10, slope = 1

Parallel lines

3 0

2 years ago

Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo

natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

P(B) is the probability of the person having cancer, so $P(B) = 0.009$

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So $P(A/B) = 0.91$

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

$P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765$

What is the probability that the person actually does have cancer?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213$

There is a 12.13% probability that the person actually does have cancer.

3 0

3 years ago

The graph of the equation below is a circle. What is the length of the radius of the circle?

storchak [24]

Answer:

Step-by-step explanation:

(X-4)2+(y+12)2=17^2

radius is square root of 17^2

4 0

2 years ago

Find the probability p(e or f) if e and f are mutually exclusive, p(e)equals 0.25, and p(f)equals 0.51.

Masteriza [31]

The definition of two events being mutually exclusive (or disjoint) only means that it is not possible for the two events to occur together. Given two events, E and F, they are mutually exclusive and also mean independent.

In this case, since events E and F are mutually exclusive, therefore the probability that either E or F will occur will simply be the sum of two events.

P (E or F) = P (E) + P (F)

P (E or F) = 0.25 + 0.51

P (E or F) = 0.76

Therefore this means that there is a 76% probability that either E or F will occur.

8 0

3 years ago