Complete question :
Birth Month Frequency
January-March 67
April-June 56
July-September 30
October-December 37
Answer:
Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.
Step-by-step explanation:
Observed value, O
Mean value, E
The test statistic :
χ² = (O - E)² / E
E = Σx / n = (67+56+30+37)/4 = 47.5
χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295
Degree of freedom = (Number of categories - 1) = 4 - 1 = 3
Using the Pvalue from Chisquare calculator :
χ² (18.295 ; df = 3) = 0.00038
Since the obtained Pvalue is so small ;
P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.
Answer:
54
Step-by-step explanation:
BEDMAS
z=10
(10)3-3(2-10)
=(10)3-3(-8)
=30-(-24) *2 negatives = a positive
=30+24
=54
Step-by-step explanation:
The way to get this is that you put them in fraction form 7/15 and then you make it equal to to x/100 and then divide the known part of the fraction which in this case is 100/15 which gives 6.67 (rounded). After you get that you multiply it by 7 which give you 46.69%
The unit rate in the equation is 20.
Option C) is the correct answer.
<u>Step-by-step explanation</u>:
Step 1 :
In the given equation y = 20x
where,
x ⇒ total number of hours for tutoring
20 ⇒ the cost per hour of tutoring
y ⇒ the total cost for total hours of tutoring
Step 2 :
Unit rate refers to the value per hour.
Here, the cost for 1 hour of tutoring is $20.
∴ The unit rate is $20 per hour of tutoring.
Answer:
Using reflexive property (for side), and the transversals of the parallel lines, we can prove the two triangles are congruent.
Step-by-step explanation:
- Since AB and DC are parallel and AC is intersecting in the middle, you can make out two pairs of alternate interior angles<em>.</em> These angle pairs are congruent because of the alternate interior angles theorem. The two pairs of congruent angles are: ∠DAC ≅ ∠BCA, and ∠BAC ≅ ∠DCA.
- With the reflexive property, we know side AC ≅ AC.
- Using Angle-Side-Angle theorem, we can prove ΔABC ≅ ΔCDA.