The 3rd set, no x or y numbers are repeated.
A = L * W
A = 4 3/4 * 3 2/5.....turn them into improper fractions
A = 19/4 * 17/5
A = 323/20 or 16 3/20 yds^2 <==
Firstly look at the options carefully and we will get to know that two answer options are incorrect because 2 of them are representing AT MOST SIGN which we don't need. So in that way Options B and D are eliminated.
So Now we are left with 2 options A and C. Lets figure it out.
We know that Carlos has 5 complete set with 4 individual figures and josh has 3 complete sets with 14 individual figures.
So lets write in the numerical language:-
let us assume that complete sets are X.
ATQ,
5x + 4 ≥ 3x + 14
subtracting 3x from both sides.
5x -3x + 4 ≥ 14
2x + 4 ≥ 14
subtracting 4 from both sides
2x ≥ 14 - 4
2x ≥ 10
dividing both sides by 2
x ≥ 5 Answer
So correct answer option is C
Assuming a normal distribution we find the standardized z scores for a:-
z1 = (80 - 180) / 25 = = -100/25 = -4
z2 = (280-180) / 25 = 4
Required P( -4 < z < 4) from the tables is >99.9%
b
z1 = 130-180 / 25 = -2
z2 = 230-180 / 25 = 2
from tables probability is 2* 0.4773 = 95.46 %
Answer:
The answer is 1.35 answer (1). You can graph both equations to give you the answer.
Step-by-step explanation:
Graph the equations and see where they intersect.