Answer:
−143x^3y^5
Step-by-step explanation:
<span>Find the odds of a man with high blood pressure dying from cardiovascular disease. 55 p .0165 3338 = p .0165 .0165 .0168 1 p 1 .0165 .9835
Do the same for a man with low blood pressure. 21 p .0079 2676 = = p .0079 .0079 .00796 1 p 1 .0079 .9921 = = = − − ----->
Calculate the odds ratio with the odds for the high blood pressure group in the numerator. Describe the result in words. HBP LBP odds .0168 odds ratio 2.11 odds .00796 = = = Men with high blood pressure are 2.11 times more likely to die from cardiovascular disease.</span>
We have that
x+4y<12
y<3
using a graph tool
see the attached figure
the solution in the attached figure
Answer:
10 years until the value of the car is 11000 dollars
Step-by-step explanation:
The value of the car after t years is modeled by the following equation:
In which V(0) is the initial value and r is the yearly depreciation ratio, as a decimal.
A new car is purchased for 21100 dollars.
This means that
The value of the car depreciates at 6% per year.
This means that . So
To the nearest year, how long will it be until the value of the car is 11000 dollars?
This is t when
To the nearest year
10 years until the value of the car is 11000 dollars
Answer:
Step-by-step explanation:
Hello!
The objective of this experiment is to test if the presence of toxaphene in the diet reduces the gain of weight. For these two random samples of female rats were made, one was fed with a diet that contained a low dose of toxaphene and the other, called the control group, was fed with the same type of food but without toxaphene. The weight of the rats was registered in both groups obtaining:
Sample 1 (with toxaphene)
n₁= 19 female rats
S₁= 58g
Sample 2 (control group)
n₂= 21
S₂= 30g
The hypothesis is that the presence of low-dose insecticide in the diet increases the variability in weight gain. Symbolically: σ₁² > σ₂²
The hypothesis is:
H₀: σ₁² ≤ σ₂²
H₁: σ₁² > σ₂²
α: 0.05
This hypothesis test is for the variance ratio, the statistic to use is:
F= (S₁²/S₂²)*( σ₁²/σ₂²)~F
This test is one-tailed (right) and the critical value is:
If F ≥ 2.19, you reject the null hypothesis.
If F < 2.19, you support the null hypothesis.
F= (S₁²/S₂²)*( σ₁²/σ₂²) = (3364/900)*1 = 3.737
Since the calculated value is greater than the critical value, the decision is to reject the null hypothesis. The variability of the weight gain of rats fed with a low dose of insecticide is greater than the variability of the control group.
I hope it helps!