All categories

4 years ago

3x^+7x-6 factor completely

Mathematics

1 answer:

Ostrovityanka [42]4 years ago

6 0

The factor for given equation $3x^2+7x-6$ is (3x-2) and (x+3).

<u>Step-by-step explanation:</u>

To find the factors of the equation,

1) Multiply the coefficient of the $x^2$ and the constant value.

⇒3×(-6)= -18.

2) Now find two numbers that can result is in -18 while multiplying and 7 (middle term or coefficient of x) while adding.

⇒9 × (-2) = -18.

9+(-2)= 7.

Now spit the equation as $3x^2+9x-2x-6$ .

= $(3x^2+9x)-(2x-6)$ .

=3x(x+3) - 2(x+3).

=(x+3)(3x-2). (by taking out the common term x+3)

∴ The factor for given equation $3x^2+7x-6$ is (3x-2) and (x+3).

You might be interested in

Find the value of each variables in the parallelogram

Ksju [112]

Answer:

C = 6

D = 10

Step-by-step explanation:

C + 5 = 11

C + 5 -5 = 11 -5

C = 6

D + 4 = 14

D + 4 -4 = 14 -4

D = 10

4 0

3 years ago

How to convert 5 3/8 to a inproper fraction

Mila [183]

Answer:

43/8

Step-by-step explanation:

if you split 5 into parts of 8 than that becomes 40/8 plus the 3/8 is 43/8

7 0

3 years ago

Read 2 more answers

Evaluate log2/3 (4/9)

OlgaM077 [116]

Answer:

Step-by-step explanation:

8 0

3 years ago

At noon, the temperature is 76°F.

sergiy2304 [10]

Answer:

25%

Step-by-step explanation:

% Change = Change ÷ Original × 100

% Change = 19 ÷ 76 × 100

% Change = .25 × 100

% Change = 25

6 0

3 years ago

Using the method of completing the square, put each circle into the form

tatiyna

Answer:

Standard form: $(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Center: $(\frac{1}{2}, 0)$

Radius: $r =\sqrt{15}$

Step-by-step explanation:

The equation of a circle in the standard form is

$(x-h)^{2} + (y-k)^{2} = r^{2}$

Where the point (h, k) is the center of the circle

To transform this equation $4x^{2} -4x + 4y^{2} - 59 = 0$ this equation in the standard form we use the method of square.

First, we group similar variables

$(4x^{2} -4x) + (4y^{2}) - 59 = 0$

Divide both sides of equality by 4

$(x^{2} -x) + (y^{2}) - 14.75 = 0$

Now we complete square for variable x.

Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

$b =-1\\\\\frac{b}{2}= \frac{-1}{2}= -\frac{1}{2}\\\\(\frac{b}{2})^2= (-\frac{1}{2})^2 = \frac{1}{4}$

Now add $(\frac{b}{2})^2$ on both sides of the equality

$(x^{2} -x +\frac{1}{4}) + (y^{2}) - 14.75 = (\frac{1}{4})$

Factor the expression and simplify the independent terms

$(x-\frac{1}{2})^2 + (y^{2}) = 15$

$(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Then

$h =\frac{1}{2}\\\\k=0$

and the center is $(\frac{1}{2}, 0)$

radius $r =\sqrt{15}$

3 0

3 years ago