Answer:
C) 16, 6
Step-by-step explanation:
- Set AB and DC equal to eachother. 4x = x + 12.
- Subtract x from both sides. 3x = 12
- Divide by 3 to get x alone. x = 4
- Plug this x value in the equation for AB. 4•(4) = 16
- We know the AD equals 6, so that will be one of the values and we now know that AB equals 16.
Answer:
Step-by-step explanation:
You do what's in the innermost brackets first, unless you have an unknown variable.
I'll draw it for you cause im nice.
Ok so if you have 5ft on a square, all the sides are 5ft.
That mean that if its in half, one of the sides will be 2.5ft.
Now you can add 2.5 + 2.5 + 5+5 = 15.
So its 15 ft.
Answer:
For tingle #1
We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.



We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.
For triangle #2
In this one, we can find everything and there is one one value for each.
- We can find side c
Since we have a right triangle, we can find side c using the Pythagorean theorem






- We can find angle C using the cosine trig identity




- Now we can find angle A using the triangle sum theorem



For triangle #3
Again, we can find everything and there is one one value for each.
- We can find angle A using the triangle sum theorem



- We can find side a using the tangent trig identity




- Now we can find side b using the Pythagorean theorem




Answer:
16: y=4x+14 17: 12 18: when you simplify it all individually you get x=3 for both equations. 19: $6.69
Step-by-step explanation:
16:y-2=4(x+3) distribute 4 and get y-2=4x-12. Add 2 to both sides to get y-4x+14.
17:x+2y=4 and 3x+6y=? divide 3x+6y by three and you get x+2y=4. This means you can just multiply the 4 by 3 to get the answer.
18:3x-5=4 and 3x-3=6. For the first one add 5 to both sides to get 3x=9 then divide both side by 3 to get x=3. For the second one add 3 to both sides to get 3x=9. Again divide both sides by three to get x=3.
19: $18-$4.62=13.38 since he wants 2 models divide 13.38 by 2 to get 6.69.