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siniylev [52]
3 years ago
14

6,15,16,20,13,5,10,16 find the mean

Mathematics
2 answers:
ziro4ka [17]3 years ago
8 0

6 + 15 + 16 + 20 + 13 + 5 + 10 + 16 = 101/8 = 12.6

mean: 12.6

Ne4ueva [31]3 years ago
3 0

Hello There!

To find the mean we have to add up all the numbers and divide by how many numbers there are.

6+15+16+20+13+5+10+16

Now, I will add 2 numbers at a time to make it easier for myself.

21+36+18+26

Once I add up these numbers, I will get a sum of 101

Finally, I divide 101 by 8 and get a quotient of 12.625

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Select the objects that hold the same amount of liquid as a 128−fluid-ounce jug. Select all that apply. A three 8−ounce fluid gl
Salsk061 [2.6K]
The correct answers are C, D, and E.

1 quart = 32 fl oz
1 pt = 16 oz

Using these conversions you will multiply the number of quarts or pints by the number of ounces in each and then add the totals together to find if they equal 128 oz.

C.   4 x 32 = 128 oz
D.  2 x 32 + 8 x 8 = 128 oz
E.  3 x 32 + 2 x 16 = 128 oz
8 0
3 years ago
There are 19 identical socks. How many pairs of socks are there? Will there be any socks without a match? If so, how many?
9966 [12]
Each pair has 2 socks so 19÷2= 9 with 1 remaining unmatched sock.
6 0
2 years ago
Read 2 more answers
-2(x - 5) = -14 PLEASEEEEE HELPPPPPP
juin [17]
Okay so you need to start off by using the distributive property, meaning you are going to multiply -2 by both items within the parentheses. this gives you -2x + 10 = -14. from here you want to isolate x, so you’ll subtract both sides by 10 to move it to the other side. this gives you -2x=-24. then you’ll divide both sides by -2 to completely isolate x. this gives you x=12. does that make sense?
8 0
3 years ago
What is the value of m(7+9)n, when m = 0.5 and n = 2?
stepladder [879]

Answer:

16

Step-by-step explanation:

Plug things in then use PEMDAS:

m * (7+9) * n

= 0.5 * (7+9) * 2

= 0.5 * 16 * 2

= 16

4 0
2 years ago
Read 2 more answers
Consider rolling two fair dice one 3-sided the other 5-sided
Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

1\leq x\leq 3,\quad 1\leq y \leq 5

We have P(X=x)=\frac{1}{3} and P(Y=y)=\frac{1}{5}, because the dice are fair.

Now we use the assumption of independence to claim that

P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

  • 2 in a unique way (1+1)
  • 3 in two possible ways (1+2, 2+1)
  • 4 in three possible ways
  • 5 in three possible ways
  • 6 in three possible ways
  • 7 in two possible ways
  • 8 in a unique way

This implies that the probabilities of the outcomes of W=X+Y are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

8 0
3 years ago
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