We need to account for both x values on either side of the length, and width.
Thus, the length becomes 10 + x + x = 10 + 2x
and the width becomes 5 + x + x = 5 + 2x
For the second question, I'm assuming we don't account for the area that is covered by the garden.
Then we can say that the path is measured by: (5 + 2x)(10 + 2x) - 50, which is the area of the garden itself.
(5 + 2x)(10 + 2x) - 50 = 54
Expanding the brackets:






x = -9, or x = 3/2
Since x > 0, then x ≠ -9
Thus, the only x-value we can take is x = 3/2
Answer:

Step-by-step explanation:
You divide 3 from both sides leaving you with g=(x/3)-(2/3)
Please mark my answer as brainlyest.
Probably Just The Variable
Answer:
i) 7x + 8 = -90
<=> 7x = -98
<=> x = -98/7
<=> x = -14
ii) 5y - 4 = 2y - 25
<=>3y = -21
<=> y = -21/3
<=> y = -7
iii) 4(p + 3) = 36
<=> p + 3 = 36/4
<=> p + 3 = 9
<=> p = 9 - 3
<=> p = 6
iv) 2 (4f + 3) = 3 (2f + 6)
<=> 8f + 6 = 6f + 18
<=> 2f = 12
<=> f = 12/2
<=> f =6
Hope this helps!
:)
What do you mean? its a question, but you asked how to start a question???
im confused :/