Factor the following polynomial: 7x (a - b) - 3y (a

PLEASE HELP!!!!!! :)

trasher [3.6K]

Answer:

C: -19

6 to 7=13

7 to 8=15

8 to 9=17

9 to 10=19

3 0

3 years ago

PLS HELP ME I DON'T GET IT

EastWind [94]

Answer:

put g beside the four but make sure it lines up in the one line

8 0

4 years ago

Help please! really appreciate it

arlik [135]

Answer:

x=26

Step-by-step explanation:

exterior angles theorem meaning they're equal to each other.

5x+7=8x-71

add 71 to 7

5x+78=8x

subtract 5x from 8x

78=3x

divide 78 and 3

x=26

to check your work plug 26 into each equation:

5(26)+7= 137°

8(26)-71= 137°

because they're the same you know that x must equal 26

hope this helps!❤

4 0

4 years ago

In a family’s monthly budget, 2/5 of the income is spend on housing and 1/5 of the income is spent on food. How would you determ

aniked [119]

Answer:

2/5 is left

Step-by-step explanation:

Add the two you have so far together. 2/5+1/5=3/5

So 3/5 of your budget is used. 3/5 is a fraction, meaning that 5 is the whole.

Subtract 3 from 5 and you get 2. There are 2/5 left in the budget for everything else.

5 0

3 years ago

A random sample of 9 fields of corn has a mean yield of 40.6 bushels per acre and standard deviation of 7.52 bushels per acre. D

zaharov [31]

Answer:

The critical value that should be used in constructing the confidence interval is -1.397 and 1.397.

80% confidence interval for the true mean yield is [37.1 bushels per acre, 44.1 bushels per acre].

Step-by-step explanation:

We are given that a sample of 1584 third graders, the mean words per minute read was 35.7. Assume a population standard deviation of 3.3.

Firstly, the pivotal quantity for 80% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean yield = 40.6 bushels per acre

s = sample standard deviation = 7.52 bushels per acre

n = sample of fields of corn = 9

$\mu$ = true mean yield

Here for constructing 80% confidence interval we have used One-sample t test statistics as we don't know about the population standard deviation.

So, 99% confidence interval for the true mean yield, $\mu$ is ;

P(-1.397 < $t_8$ < 1.397) = 0.80 {As the critical value of t at 8 degree of

of freedom are -1.397 & 1.397 with P = 10%}

P(-1.397 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.397) = 0.80

P( $-1.397 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.397 \times {\frac{s}{\sqrt{n} } }$ ) = 0.80

P( $\bar X-1.397 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.397 \times {\frac{s}{\sqrt{n} } }$ ) = 0.80

80% confidence interval for $\mu$ = [ $\bar X-1.397 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.397 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $40.6-1.397 \times {\frac{7.52}{\sqrt{9} } }$ , $40.6+1.397 \times {\frac{7.52}{\sqrt{9} } }$ ]

= [37.1 , 44.1]

Therefore, 80% confidence interval for the true mean yield is [37.1 bushels per acre, 44.1 bushels per acre].

7 0

4 years ago

Factor the following polynomial: 7x (a - b) - 3y (a - b)