Answer:
option B
Step-by-step explanation:
since DA and CB are equal and originate from same line segmnet, they are parallel, so angle D and angle C are equal, angle A and anfle B are equal and angle E is the same for both,
Answer:
Let two consecutive multiples of 3 be x and (x+3)
A/q,
x * (x+3) = 648
➡ x² + 3x = 648
➡ x² + 3x -648 = 0
➡ x² + 27x - 24x -648 = 0
➡ x ( x + 27 ) -24 ( x +27)
➡ ( x - 24) ( x + 27)
➡ x = 24 and x = -27
so, we take x = 24.
Required multiples of 3
➡ x = 24
➡ x +3 = 24+3 = 27.
3/2 We look for a number that goes into both 9 and 6 without leaving a remainder, and that number is 3
Answer:
The correct answer is b.
Step-by-step explanation:
The wave equation is given generally as:
c(x, t) = Acos(kx - wt)
Where A = amplitude
k = wave number
w = angular frequency.
x = horizontal distance moves by the wave.
t = time
The options show to us that the wave depends only on t and not (x, t).
Hence, the wave equation becomes:
c(t) = Acos(wt)
Given that:
A = 5 V
f = 1 * 10⁶ Hz
Angular Frequency, w, is given as:
w = 2πf
w = 2 * π * 1 * 10⁶ Hz
w = 2π(1 * 10⁶)
The wave equation becomes:
c(t) = 5cos(2*π*1*10⁶)
The correct answer is b.
Your answer is D.
Will always be x2 and y2 starting off
