Question

What is the area of the figure? Enter your answer in the box.

Answer 1

112 I believe but I may be incorrect

Answer 2

Here the figure is sum of a square and a right angled triangle.

We know that square has equal four sides. Here the length of the side of square = 10 inch.

We know that formula to find area of a square is $a^2$, where a is the side of the square.

By substituting the value of a in the formula we will get,

The area of the square = $(10)^2$ = 100 square inches.

Now we have the right angled triangle.

To find the base of the triangle we will subtract 6 from the side length of the square.

So base of the triangle = $(10-6)$ = 4 inches.

To get height of the triangle we will subtract the side length of the square from 16. We will get,

$(16-10)$ = 6 inches.

Now we know that the formula to find the area of the triangle = $\frac{1}{2} bh$, where b is the base and h is the height.

Here we have b = 4 inches and h = 6 inches.

The area of the triangle

= $\frac{1}{2}(4)(6)$

= $\frac{1}{2}(24)$

= $12$

So area of the triangle = 12 square inches.

Now total area of the figure is sum of area of the square and area of the triangle.

Total area = $(100+12)$ square inches = 112 square inches.

We have got the required answer.

The total area of the figure = 112 square inches.