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3 years ago

What is the smallest possible whole number value of x

Mathematics

1 answer:

Pepsi [2]3 years ago

5 0

Answer:

Absolutely anything! It all depends on what the equation is. Variables can be any number with exception of 0 As a denominator. Otherwise pick anything as long as the end results come out to the number you are seeking.

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What is the value of the expression shown below?

o-na [289]

Answer:

Step-by-step explanation:

1.6/0.2=8

10⁵-10²=10³

3 0

3 years ago

3A + 4N - 5A + 3 - 8N + 11 =

Anit [1.1K]

Answer:

-2a-4n+14

Step-by-step explanation:

7 0

3 years ago

автобус прошел 220 км за 27/7 часа.Сколько километров пройдет автобус за 54/7часа с той же скоростью?

egoroff_w [7]

Отвечать:

440 км

Пошаговое объяснение:

Учитывая, что :

Пройденное расстояние за 27/7 часов = 220 км

Расстояние, которое необходимо преодолеть за 54/7 часов, составит x

Следовательно, мы можем настроить перекрестное умножение:

27/7 = 220

54/7 = х

Крест умножить

27/7 х = 220 * 54/7

27x / 7 = 11880/7

3.8571428x = 1697.1428

х = 1697,1428 / 3,8571428

х = 439,99999

x = 440 км

Таким образом, за 54/7 часов будет преодолено расстояние 440 км.

4 0

2 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago

HELPPPPPPP !!!!! Select the statements that are true based on the following given information.

almond37 [142]

the anwser is ]123[8D[

7 0

3 years ago