Answer:
adds up the values in the range of cells provided
Explanation:
According to your code, you are setting the first element of the customerAges list as your baseline age. You then use a for loop to check each item in the list to see if it is less than your minimum variable. Then you assign the item to the minimum.
The missing line of code is b, if minimum > item:
I hope this helps!
Answer:
What’s up, I’m currently in this class, and I was wondering if it’s easy or hard?
Explanation:
Answer:
def occurencesOfWords(words,freq):
frequency_dictionary={}
matched_frequency_words=[]
for i in range(len(words)):
counter=1
a=words[i].lower()
for j in range(len(words)):
if(i==j):
continue
b=words[j].lower()
if(a==b):
counter+=1
frequency_dictionary[words[i]]=counter
for key in frequency_dictionary:
if(frequency_dictionary[key]==freq):
matched_frequency_words.append(key)
return matched_frequency_words
if __name__=='__main__':
user_input=input()
freq=int(input())
words=user_input.split(" ");
required_words=occurencesOfWords(words,freq)
for s in required_words:
print(s)
Explanation:
- Inside the occurencesOfWords function, initialize a frequency_dictionary that is used to store the string and the frequency of that specific string
.
- matched_frequency_words is an array that is used to store each string whose frequency matches with the provided frequency
- Run a nested for loop up to the length of words and inside the nested for loop, skip the iteration if both variables i and j are equal as both strings are at same index.
- Increment the counter variable, if two string are equal.
- Loop through the frequency_dictionary to get the matching frequency strings
.
- Finally test the program inside the main function.
