3*25=75
so the question is 75/8
you would 10 packages since
8*8=64
8*9=72
but 8*10=80 is enough, remainder 5
Answer:
Step-by-step explanation:
can you upload diagram?
For 12:
Since the line y = mx + c is a tangent, then the distance from the centre of the circle to the line is equal to the radius.
Using perpendicular distance:
![d = r = \frac{| -m \cdot a + 1 \cdot b - c |}{\sqrt{(-m)^{2} + 1}}](https://tex.z-dn.net/?f=d%20%3D%20r%20%3D%20%5Cfrac%7B%7C%20-m%20%5Ccdot%20a%20%2B%201%20%5Ccdot%20b%20-%20c%20%7C%7D%7B%5Csqrt%7B%28-m%29%5E%7B2%7D%20%2B%201%7D%7D)
![r = \frac{|b + am - c|}{\sqrt{m^{2} + 1}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B%7Cb%20%2B%20am%20-%20c%7C%7D%7B%5Csqrt%7Bm%5E%7B2%7D%20%2B%201%7D%7D)
Squaring both sides, we get:
![r^{2} = \frac{(b - c + ma)^{2}}{m^{2} + 1}](https://tex.z-dn.net/?f=r%5E%7B2%7D%20%3D%20%5Cfrac%7B%28b%20-%20c%20%2B%20ma%29%5E%7B2%7D%7D%7Bm%5E%7B2%7D%20%2B%201%7D)
![(1 + m^{2})r^{2} = (b - c + ma)^{2}](https://tex.z-dn.net/?f=%281%20%2B%20m%5E%7B2%7D%29r%5E%7B2%7D%20%3D%20%28b%20-%20c%20%2B%20ma%29%5E%7B2%7D)
, as required.
The answer is 56 square meters
I would use hours however it depends the length of time you intend on spending on it. Typically you’d use the larger unit if the time elapsed passes one unit of the larger unit
i would use hours unless you are going to spend a minute or so