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Basile [38]
4 years ago
13

What non-negative integers are solutions of the inequality |2x - 1| < 3 ?

SAT
1 answer:
matrenka [14]4 years ago
7 0
All positive solutions, including zero:

2x - 1 < 3

2x < 4

x < 2

solutions (integers): 0 and 1

All negative solutions:

2x - 1 < -3

2x < -2

x < -1

Since the question is asking you for solutions that are non-negative integers, the answer is 0 and 1.
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A: by explaining why working together is necessary for success.

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Roman rulers who had absolute power assumed the title of __________. a. consul b. dictator c. senator d. censor please select th
netineya [11]

Answer:

B. Dictator

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Hope it helped !  

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2 years ago
Decide whether the elements of a typical conclusion paragraph are in the correct order.
timurjin [86]

The correct answer to this open question is the following.

Decide whether the elements of a typical conclusion paragraph are in the correct order.

So this is the correct order.

1.- summary of the main thesis.

2.- restatement thesis.

3.- satisfying close.

This is the explanation. When you are writing a conclusion, you have to be precise, summarize the main ideas of the document, not adding something new or different, restate the thesis, and give direct-to-the-point closing ideas so the reader can get the main purpose of the document clear.

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4 0
3 years ago
The functions $f$ and $g$ are defined as follows: \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\quad\text{and}\quad g(x) = \dfrac{\sqrt{x+1}}
AlladinOne [14]

Recall that √x has a domain of x ≥ 0.

So, f(x) is defined as long as

(x + 1)/(x - 1) ≥ 0

• We have equality when x = -1

• Otherwise (x + 1)/(x - 1) is positive if both x + 1 and x - 1 are positive, or both are negative:

\begin{cases}x+1>0 \implies x>-1 \\ x-1>0 \implies x>1\end{cases} \implies x > 1

\begin{cases}x+1

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On the other hand, g(x) is defined by two individual square root expressions with respective domains of

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• x - 1 ≥ 0   ⇒   x ≥ 1

but note that g(1) is undefined, so we omit it from the second domain.

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x > 1

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andreev551 [17]
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