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LekaFEV [45]
3 years ago
15

Budgeted sales are: Month Sales revenue August $15,000 September $15,000 October $14,000 November $13,000 December $20,000 You c

ollect 50% of sales revenue as cash in the month of the sale, 40% in the following month, and 10% two months after the sale. a) Compute budgeted cash inflows for October and November: October = $ November = $ Remember to go backwards in time: e.g., 40% of September revenue is collected in the following month (October). This implies that cash inflows for October include 40% of sales from the previous month (September).
Business
1 answer:
stepladder [879]3 years ago
3 0

Answer:

The budgeted cash inflows for October and November is $14,500 and $12,300 respectively

Explanation:

The computation of the budgeted cash inflows for October and November is shown below:

For October:

= 50% of sales revenue of October + 40% of sales revenue of September + 10% of August

=  0.5 × $14,000 + 0.40 × $15,000 + 0.10 × $15,000

= $7,000 + $6,000 + $1,500

= $14,500

For November

= 50% of sales revenue of November + 40% of sales revenue of October + 10% of September

=  0.5 × $13,000 + 0.40 × $14,000 + 0.10 × $15,000

= $5,200 + $5,600 + $1,500

= $12,300

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Answer:

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Explanation:

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3 years ago
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Cassie's Quilts alters, reconstructs, and restores heirloom quilts. Cassie has just spent $800 purchasing, cleaning, and reconst
Nataliya [291]

Answer:

The correct option is B.

Explanation:

The marginal benefit is the maximum amount which a person or individual is willing to pay in order to have an additional service or benefit. It is the additional satisfaction, which the person receives when an additional service or good is purchased.

So, in this case, Cassie need or require some special fabric which cost her $200 that is the additional amount she need to pay in order to complete the task. But alternatively, she could sell the quilt for $900. Therefore, she had a marginal benefit of $900, if sells the quilt as is now.

3 0
3 years ago
Joshua needed money for some unexpected expenses, so he borrowed $5,355.26 from a friend and agreed to repay the loan in seven e
konstantin123 [22]

Answer:

10%

25.14 years

Explanation:

A financial calculator can be used to solve these problems

PMT = $-1,100

PV = $5,355.26

FV = 0

N = 7

Compute I = 10%

PMT = $-25,000

FV =  $1,387,311

I = 6%

PV = 0

Compute N = 25.14 years

8 0
4 years ago
Two weeks before his performance appraisal, John successfully resolved a service complaint involving one of the company’s most i
Sergeu [11.5K]

Answer:

The correct answer is Recency error.

Explanation:

Focus on the most recent performance evaluated: The evaluators can be guided by the most recent actions and / or attitudes, whether negative or positive, without considering the history of the collaborators. This error can give an unfair result and nothing representative.

A recency error is an inaccuracy or failure in the performance evaluation or job interview, caused by the dependence of the evaluator or the interviewer on the most recent events of the employee or applicant behavior.

5 0
3 years ago
A university officer wants to know the proportion of registered students that spend more than 20 minutes to get to school. He se
vlada-n [284]

Answer:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

Explanation:

For this case we assume that the question is: If in the experiment described we can use the normal approximation for the proportion of interest.

For this case we have a sample of n =25

And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.

X = 13 represent the number of students in the sample selected that have a time more than 20 min.

And then the estimated proportion of interest would be:

\hat p = \frac{X}{n}= \frac{13}{25}= 0.52

And we want to check if we can use the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So in order to do this approximation we need to satisfy some conditions listed below:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition:

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

3 0
3 years ago
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