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Eddi Din [679]
3 years ago
8

Diona told me to get this app to solve my math problems,what is 10 + 10 Jean can't help because she's doing other stuff :,)​

Mathematics
1 answer:
elena55 [62]3 years ago
5 0

Answer:

20

Step-by-step explanation:

10 + 10

= 20

Just add units place first.

0 + 0 = 0

Then tens place.

1 + 1 = 2

So the number,

=> 20

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Please need help with this one
konstantin123 [22]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape....
frosja888 [35]

Answer:

About 41.5%

Step-by-step explanation:

<em>Given:</em>

<em>A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape.</em>

<em>To Find:</em>

<em>What is the probability that both grapes are red?</em>

<em>Answer choices:</em>

<em>about 39.7%</em>

<em>about 41.5%</em>

<em>about 42.5%</em>

<em>about 44.5%</em>

<em>Solution:</em>

<em>Since, there are 8 green grapes and 15 red grapes, the total number of grapes is 23 .</em>

<em>As the red grapes are 15..</em>

<em>Thus,</em>

<em>The probability of choosing a red grape the first time is 15/23.</em>

<em>Because out of the total 23 grapes only 15 were red grape.</em>

<em>The probability of choosing the red grape the second time will be 14/22. Because the number of red grapes has already decreased by one and so is the total number of grapes after first choice</em>

<em>Hence, the probability of choosing or eating two red grapes will be :</em>

<em>15/23×14/22</em>

<em>=105/253</em>

<em>=0.415</em>

<em>= 41.5%</em>

<em>Therefore, the probability that both grapes are red is about 41.5%</em>

5 0
2 years ago
The price of a watch was increased by 20% to £162. What was the price before the increase?
vfiekz [6]

Answer:

= £135

Step-by-step explanation:

Original price = 100%

Percentage increase = 20%

New price = 100% + 20% = 120%

If 120% = £162

What about 100% = ?

= (100 x 162) ÷ 120

= 16200 ÷ 120

= £135

6 0
3 years ago
Read 2 more answers
find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
3 years ago
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
4 years ago
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