Answer:
f(-2) = - 4
Step-by-step explanation:
f(x) = x² + 3x - 2
f(-2) = ( -2)² + 3 *(-2) - 2
= 4 - 6 - 2
= 4- 8
= - 4
Hope it will help :)
Answer:
y = -3x + 1
Step-by-step explanation:
- Start by picking any two points on the line.
(-1, 4) and (1, -2)
- Now, use the slope formula to find the slope.
m = y^2 - y^1 / x^2 - x^1
m = -2 - 4 / 1 - (-1)
m = -6 / 1 + 1
m = -6/2
m = -3
So, our slope is -3.
- Let's find the y-intercept now using the slope-line equation:
y = mx + b
4 = -3(-1) + b
4 = 3 + b
-3 -3
---------------------
1 = b
- Lastly, let's put our findings into the slope-line equation:
y = mx + b
slope is -3 and y-intercept is 1
y = -3x + 1
You find a common denominator which would be 36. 12 times 3 is 36 and 8 times 3 is 24. so 24 over 36 is equal to 12 over 18. x = 12
Answer:
The absolute value function shows up in the world around us in many different areas. Suppose you are driving down the road and you look out your window and see a speed limit sign that says the speed limit is 50mph. You look at your speedometer and see that you're driving at 45mph, so you are going 5mph below the speed limit. Notice that even though you are going 5mph below the speed limit, we don't say you are going -5mph from the speed limit. We just state the difference from 50mph as a positive value. A road sign shows a vehicle's speed as the vehicle passes. SPEED LIMIT 30 YOUR SPEED Part A: The sign blinks for vehicles traveling within 5 mi/h of the speed limit. Write and solve an absolute value inequality to find the minimum and maximum speeds of an oncoming vehicle that will cause the sign to blink. Part B: Another sign blinks when it detects a vehicle traveling within 2 mi/h of a 35 mi/h speed limit. Write and solve an absolute value inequality to represent the speeds of the vehicles that cause the sign to blink.
Step-by-step explanation:
