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iren [92.7K]
3 years ago
14

Given that point A(4,2) and AC-> = (-7, 3) , find |CA->|

Mathematics
1 answer:
Ket [755]3 years ago
5 0
C =hays s duhh dhsududhbrhsudvd
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If sin Θ = negative square root 3 over 2 and π < Θ < 3 pi over 2, what are the values of cos Θ and tan Θ? cos Θ = negative
andreev551 [17]

Answer:

The correct option is the option with:

cos Θ = 1/2

tan Θ = -√3

Step-by-step explanation:

Given that

sin Θ = -√3/2

We want to find the values of

cos Θ and tan Θ

First of all,

arcsin (-60) = -√3/2

=> Θ = 60

tan Θ = (sin Θ)/(cos Θ)

tan Θ = (-√3/2)/(cos Θ)

cos Θ tan Θ = (1/2)(-√3)

Knowing that Θ = -60,

and cos Θ = cos(-Θ), comparing the last equation, we have

cos Θ = 1/2

tan Θ = -√3

8 0
3 years ago
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________ is a fundamental difference between the t statistic and a z-score
chubhunter [2.5K]

Answer:

Step-by-step explanation:

- The Z-score allows you to decide if your sample is different from the population mean. In order to use z, you must know four things:

  • The population mean.
  • The population standard deviation.
  • The sample mean.
  • The sample size.

- Usually in stats, you don’t know anything about a population, so instead of a Z score you use a T-Test with a T Statistic.

- The major difference between using a Z score and a T statistic is that you have to estimate the population standard deviation. The T test is also used if you have a small sample size (less than 30).

6 0
3 years ago
HELP! can someone help me with this math problem pls?
scoray [572]

The answer to this is 180.

5 0
4 years ago
A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.
Reptile [31]

Answer:

a.P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}

Step-by-step explanation:

We are given that a linear differential equation

y''+2y=e^{3x}+x^3

We have to find the particular solution

P.I=\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}

P.I=\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}

P.I=\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3

P.I=\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0} (higher order terms can be neglected

P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.Characteristics equation

D^2+2=0

D=\pm\sqrt2 i

C.F=C_1cos \sqrt2x+C_2 sin\sqrt2 x

G.S=C.F+P.I

G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)

3 0
4 years ago
I will give Brainiest if you are right
Vadim26 [7]

Answer:

19.5º

Step-by-step explanation:

Every triangle is equal to 180º for all angles. So, you add 33.5 + 127 and subtract the sum by 180.

33.5 + 127= 160.5

180- 160.5 = 19.5

So, the angle F is 19.5º

Hope this helps !!

-Ketifa

8 0
3 years ago
Read 2 more answers
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