Answer:
huh????
Step-by-step explanation:
Answer:
1/3 is rational its nonterminating but it repeats
6.99999 rational its nonterminating and it repeats also
7.48331 is irrational because its non terminnating and it does not repeat
Step-by-step explanation:
Answer:
Natural Numbers, Whole Numbers, and Integers are rational numbers.
Example: {1, 2, 3, -1, -2, -3}
Numbers with repeating decimals and terminating decimals are also rational.
Example: {2.34343434..., 3.45}
If a square root makes a perfect square, then it is rational.
Example: {√16, √100}
Hope this helps.
Option first and option second are correct because the common difference of the sequence is the same as the slope of the graph.
<h3>What is a sequence?</h3>
It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
The question is incomplete.
The question is:
What can be concluded about the sequences 19, 15, 11, 7, . . . represented on the graph? Check all that apply.
- The common difference of the sequence is the same as the slope of the graph.
- The slope of the graph is –4.
- The next term in the sequence is represented by point (4, 3).
- f(x) = –4x + 19 represents the sequence.
- An infinite number of points can be determined to follow this sequence.
The graph is attached to the picture please refer to the graph.
We have an arithmetic sequence:
19, 15, 11, 7,...
The first term is:
a = 19
Common difference d = 15-19 = -4
The nth term:
a(n) = 19 + (n-1)(-4)
a(n) = 19 -4n + 4
a(n) = -4n + 23
We can write above expression as:
f(x) = -4x + 23
Slope of the equation = -4
The correct options are:
- The common difference of the sequence is the same as the slope of the graph.
- The slope of the graph is –4.
Thus, an option first and option second are correct because the common difference of the sequence is the same as the slope of the graph.
Learn more about the sequence here:
brainly.com/question/21961097
#SPJ1
AFC = FC / Quantity printed
<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>
<span>ATC = TC / Quantity printed </span>
<span>where TC = FC + Variable C * Quantity printed </span>
<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>
<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>
<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>