Can someone help me with this?

Mathematics

1 answer:

Natalka [10]2 years ago

6 0

Downloading photo math from the app store are wonderful resources when having trouble with math. Hope this helps!

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A triangular bandana has an area of 46 square inches. The height of the triangle is 5 3 4 inches. Enter and solve an equation to

shutvik [7]

Answer: 16 inches

Step-by-step explanation:

The area of a triangle = bh/2

where b = base = unknown

h = height = 5 3/4 inches

Area = 46 inches²

Therefore, 46 = base × 5 3/4 / 2

Cross multiply

46 × 2 = base × 5 3/4

92 = base × 5 3/4

Base = 92 ÷ 5 3/4

Base = 92 ÷ 23/4

Base = 92 × 4/23

Base = 4 × 4

Base = 16 inches

8 0

2 years ago

Sin^2(x/2)=sin^2x <br> Find the value of x

Veronika [31]

$\sin^2\dfrac x2=\sin^2x$
$\dfrac{1-\cos x}2=1-\cos^2x$
$1-\cos x=2-2\cos^2x$
$2\cos^2x-\cos x-1=0$
$(2\cos x+1)(\cos x-1)=0$
$\implies\begin{cases}2\cos x+1=0\\\cos x-1=0\end{cases}$ $\implies\begin{cases}\cos x=-\frac12\\\cos x=1\end{cases}$

The first case occurs in $0\le x$ for $x=\dfrac{2\pi}3$ and $x=\dfrac{4\pi}3$ . Extending the domain to account for all real $x$ , we have this happening for $x=\dfrac{2\pi}3+2n\pi$ and $\dfrac{4\pi}3+2n\pi$ , where $n\in\mathbb Z$ .

The second case occurs in $0\le x$ when $x=0$ , and extending to all reals we have $x=2n\pi$ for $n\in\mathbb Z$ , i.e. any even multiple of $\pi$ .