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Nataliya [291]
3 years ago
14

What is the length of a side of a cube with volume 729 cm3?

Mathematics
1 answer:
adell [148]3 years ago
3 0
CubeSolve for edgea≈9cm
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Evaluate 13 - 5 + 7).<br> help pleaseee
natali 33 [55]
13-5=8

8+7=15 answer is 15
8 0
2 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
Which set of numbers are equivalent?
Karolina [17]

Answer:

C

10% = (10÷100=1÷10)=2÷20=.10

8 0
3 years ago
Hey i need some help :)
melamori03 [73]

Answer:

[See Below]

Step-by-step explanation:

\boxed{Hey~There!}

__________________________________________________________

\boxed{Solve~-3x

  • Rearrange the equation by subtracting what is to the right of the greater than sign (≤, ≥) from both sides of the inequality:

                 -3*x-(9)

  • Pull out like factors:  

                -3x - 9  =   -3 * (x + 3)

  • Divide both sides by -3:
  • Remember to flip the inequality sign:

                 

  • Subtract 3 from both sides:

                 x > -3

\boxed{The~answer~is: x > -3}

\boxed{The~answer~is: C}

__________________________________________________________

Hope~this~helps~Mate!\\-Your~Friendly~Answerer,~Shane  ^-^

8 0
2 years ago
The figure is made from squares of different sizes.Find the area of A if the side of each of the two indentical smallest square
Temka [501]

Answer:

The area of square A is 256 cm²

Step-by-step explanation:

  • <em>The four sides of a square are equal in length</em>
  • <em>Area of a square = side × side</em>

In the given figure

∵ The sides of the square E = 2 cm each

∵ The sides of the square F = 2 cm each

∵ The side of square D is the sum of the sides of squares E and F

∴ The sides of the square D = 2 + 2 = 4 cm each

∵ The side of square C is the sum of the sides of squares E and D

∴ The sides of square C = 2 + 4 = 6 cm each

∵ The side of square B is the sum of the sides of squares C, E, and F

∴ The sides of square B = 6 + 2 + 2= 10 cm each

∵ The side of square A is the sum of the sides of squares B, F, and D

∴ The sides of square A = 10 + 2 + 4= 16 cm each

∵ Area of square A = side × side

∴ Area of square A = 16 × 16

∴ Area of square A = 256 cm²

∴ The area of square A is 256 cm²

3 0
2 years ago
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