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Nataliya [291]
3 years ago
14

What is the length of a side of a cube with volume 729 cm3?

Mathematics
1 answer:
adell [148]3 years ago
3 0
CubeSolve for edgea≈9cm
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Green Leaf Lawn Care had 64 customers under contract at the start of the year. The company's owner expects his new radio adverti
IRINA_888 [86]

Answer:

C. c = 64 + 2w

Step-by-step explanation:

You're starting with 64 customers and you're gaining 2 for each week.

<em>good luck, i hope this helps :)</em>

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3 years ago
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How do I solve this??
Strike441 [17]

Answer:

r = -1/2

Step-by-step explanation:

3(5 + 4r) = -18r

15 +12r = -18r by distributive property

15 = -12r - 18r

15 = -30r

r = - 1/2r

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Help needed <br> Will award brainliest
nirvana33 [79]
Q17:

one week = $560
52 weeks = 560 x 52 = $29120

Q18: 

one year = $28500
52 weeks = 28500
1 week = 28500 ÷ 52 = $548

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5% of $300000 = 0.05 x 300000 = $15000
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3 years ago
The length of a rectangle is 3 centimeters less than four times its width. Its area is 10 square centimeters. Find the dimension
Kay [80]

Answer:

W = 2 cm

L = 5 cm

Step-by-step explanation:

A rectangle is a four sided shape with 4 perpendicular angles. It has two pairs of parallel sides which are equal in distance: width and length. Its area, the amount of space inside it, can be found using the formula A = l*w. If the area is 10 cm² and the length is "3 cm less than 4 times the width" or 4w - 3, you can substitute and solve for w.

A = l*w

10 = (4w - 3)(w)

10 = 4w² - 3w

Subtract 10 from both sides to make the equation equal to 0. Then solve the quadratic by quadratic formula.

4w² - 3w - 10 = 0

Substitute a = 4, b = -3 and c = -10.

w = \frac{3 +/- \sqrt{(-3)^2 - 4(4)(-10)} }{2(4)} = \frac{3 +/- \sqrt{9 +160)} }{8} =  \frac{3 +/- \sqrt{169} }{8} = \frac{3+/-13}{8}

There are two possible solutions which can be found.

3 + 13 / 8 = 16/ 8 = 2

3 - 13 / 8 = -10/8 = -5/4

Since w is a side length or distance, it must be positive so w = 2 cm.

If the width is 2 cm then the length is 4(2) - 3 = 8 - 3 = 5 cm.

8 0
3 years ago
One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant rate from 8 p.m. to midnight. At mi
aliina [53]

Answer:

- 4.2 degrees

Step-by-step explanation:

If the drop was from temp 0 at 8 pm to temp -16.8 at midnight (4 hours later)

then,the drop is given by the rate: -16.8/4 = - 4.2 degrees per hour

Therefore, at 9 pm the temperature was:

0 degrees - 4.2 degrees = - 4.2 degrees

5 0
3 years ago
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