Answer:
a. 1.954
Step-by-step explanation:
hope this helps you!!
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Answer:
a) shown
b) h = [sqrt(17) - (5/2)t]²
c) t = 2sqrt(17)/5 seconds
Step-by-step explanation:
V = pi × r² × h
V = pi × 5² × h
V = 25pi × h
a) dV/dt = dV/dh × dh/dt
-5pi × sqrt(h) = 25pi × dh/dt
dh/dt = -sqrt(h)/5
b) 1/sqrt(h) .dh = -5. dt
2sqrt(h) = -5t + c
t = 0, h = 17
2sqrt(17) = 0 + c
c = 2sqrt(17)
2sqrt(h) = -5t + 2sqrt(17)
sqrt(h) = [2sqrt(17) - 5t] ÷ 2
sqrt(h) = sqrt(17) - (5/2)t
Square both sides
h = [sqrt(17) - (5/2)t]²
c) empty: h = 0
0 = [sqrt(17) - (5/2)t]²
sqrt(17) - (5/2)t = 0
(5/2)t = sqrt(17)
t = 2sqrt(17)/5
t = 1.64924225 seconds
sqrt: square root
Answer:
The cube root of given expression is 
.
Step-by-step explanation:
The given expression is
![\sqrt[3]{216x^9y^{18}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E9y%5E%7B18%7D%7D)
It can be written as
Use the exponent property: 
![\sqrt[3]{216x^9y^{18}}=\sqrt[3]{6^3(x^3)^3(y^6)^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E9y%5E%7B18%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E3%28x%5E3%29%5E3%28y%5E6%29%5E%7B3%7D%7D)
![\sqrt[3]{216x^9y^{18}}=\sqrt[3]{(6x^3y^6)^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E9y%5E%7B18%7D%7D%3D%5Csqrt%5B3%5D%7B%286x%5E3y%5E6%29%5E%7B3%7D%7D)
![\sqrt[3]{216x^9y^{18}}=6x^3y^6](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E9y%5E%7B18%7D%7D%3D6x%5E3y%5E6)
Therefore the cube root of given expression is .
Answer:
24 cm
Step-by-step explanation:
8+8=16
4+4=8
8+16=24 cm
*Perimeter includes adding all sides, area is multiplying all sides.
I would go with A but I am not 100% sure so you may want to check however you can.
