Answer:
see attached
Step-by-step explanation:
When the sequence of sides (shortest to longest, for example) remains the same (CW or CCW), then the number of reflections is even, possibly zero. The figure will have been <em>translated</em> if all of the corresponding sides retain their original direction, otherwise <em>rotation</em> is involved.
If the sequence is reversed, as in the upper right and lower left figures, then <em>reflection</em> is involved. The line of reflection will be the line through the midpoints of the segments connecting corresponding vertices.
Answer:
18%
Step-by-step explanation:
63/350 × 100 = 18
hope this helps
Answer:
a. dy/dx = -2/3
b. dy/dx = -28
Step-by-step explanation:
One way to do this is to assume that x and y are functions of something else, say "t", then differentiate with respect to that. If we write dx/dt = x' and dy/dt = y', then the required derivative is y'/x' = dy/dx.
a. x'·y^3 +x·(3y^2·y') = 0
y'/x' = -y^3/(3xy^2) = -y/(3x)
For the given point, this is ...
dy/dx = -2/3
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b. 2x·x' +x^2·y' -2x'·y^3 -2x·(3y^2·y') + 0 = 2x' + 2y'
y'(x^2 -6xy^2 -2) = x'(2 -2x +2y^3)
y'/x' = 2(1 -x +y^3)/(x^2 +6xy^2 -2)
For the given point, this is ...
dy/dx = 2(1 -0 +27)/(0 +0 -2)
dy/dx = -28
_____
The attached graphs show these to be plausible values for the derivatives at the given points.
Answer: y=-5x-2
Step-by-step explanation: If you type all of the options into desmos calculator you will come up with 4 different graphs. Just simply find the graph with your coordinates on it. hope this helped :)
Answer:
B. d = 5/3t
Step-by-step explanation:
The complete question is shown in the figure attached with.
We need to find the equation of direct variation using the graph. The general equation for a direction variation is:
y = kx
In this case, the variable along x axis is time in seconds i.e. "t" and the variable along y axis is distance in meters i.e. "d". So, the equation for this case would be:
d = kt
We need to find the value of "k" to complete this equation. For this we can use any point from the graph and substitute it in the above equation. From the graph we can see that the distance covered for time = 3 seconds is 5 meters. Substituting t =3 and d = 5 in above equation, we get:
5 = 3k
k = 5/3
Using the value of k in the above equation, we get:
Therefore, option B gives the correct answer
