Answer: It is possible to determine the height of the triangle by using the formula of the area of a triangle and creating an equation to find the missing value (height). Also, the value of the height is 7ft
Explanation:
The area of a triangle is found by using both the height and the base of a triangle. Indeed, the general formula for this is A( area) = h (height) x b (base) ÷ 2. Now, this general formula can be used to find any of the values missing if two values are known. This means the height can be calculated using the area and the base. To do this, create a simple equation and solve it. The process is shown below:
1. Write the general equation
![A = \frac{h b}{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7Bh%20%20b%7D%7B2%7D)
2. Replace the letters with the values you have
![21 =\frac{6b}{2}](https://tex.z-dn.net/?f=21%20%3D%5Cfrac%7B6b%7D%7B2%7D)
3. Find the missing value by moving the values to the other side of the equal symbol (=) and changing its symbol
21 x 2 = 6b -For example 2 divided 6b but if it is changed to the other side it needs to multiply
42 = 6 b
42 / 6 = b
b = 7
This means the value of the height is 7 ft. If you want to double-check this, use the original formula:
A = 6 ft x 7 ft / 2
A= 42
/ 2
A= 21 ![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)
Answer:
4x - 8 = 15
4x = 15 + 8
4x = 23 (divide both sides by 4 to get x)
4x/4 = 23/4
x = 5.75
Step-by-step explanation:
x = 5.75!!!!!
Answer: ![\text{Area of the square shaped traffic sign }=16x^2+9+24x](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20square%20shaped%20traffic%20sign%20%7D%3D16x%5E2%2B9%2B24x)
Step-by-step explanation:
Given: The side of the square shaped traffic sign = 4x+3
We know that the area of square is given by:-
![Area= side^2](https://tex.z-dn.net/?f=Area%3D%20side%5E2)
Therefore, the area of the side of the square shaped field is given by:-
![Area=(4x+3)^2](https://tex.z-dn.net/?f=Area%3D%284x%2B3%29%5E2)
We know that , ![(a+b)^2=a^2+b^2+2ab](https://tex.z-dn.net/?f=%28a%2Bb%29%5E2%3Da%5E2%2Bb%5E2%2B2ab)
Therefore,
![(4x+3)^2=(4x)^2+(3)^2+2(4x)(3)\\=16x^2+9+24x](https://tex.z-dn.net/?f=%284x%2B3%29%5E2%3D%284x%29%5E2%2B%283%29%5E2%2B2%284x%29%283%29%5C%5C%3D16x%5E2%2B9%2B24x)
Hence, ![\text{Area of the square shaped traffic sign }=16x^2+9+24x](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20square%20shaped%20traffic%20sign%20%7D%3D16x%5E2%2B9%2B24x)
∠4 = 90 (verticallyopposite)
∠2 = 68 (verticallyopposite)
∠6 = ∠2 + ∠4 (exterior angles = sum of opposite angles)
∠6 = 68 + 90 = 158°
Answer: 158°