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cricket20 [7]
3 years ago
13

What is the solution of the following quadratic inequality? x2 – 4x – 21 ≤ 0

Mathematics
2 answers:
Dominik [7]3 years ago
7 0

Answer:

3, and -7

Step-by-step explanation:

First factor the trinomial

y=x2−4x−21

.

Find 2 numbers knowing sum (-4) and product (c = - 21). They are the numbers in the factor pair (3, -7).

y = (x + 3)(x - 7)

Solving the 2 binomials, we get:

x = -3 and x = 7

trasher [3.6K]3 years ago
6 0

Answer: Its B

A number line going from negative 8 to 8. Closed circles are at negative 3 and 7. The line between the circles is shaded.

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What is the probability of you picking a weekend day from the days of the week?
svet-max [94.6K]

Answer:

3/7

Step-by-step explanation:

its 3/7 because there are 3 weekend days and there are 7 days in total in one week, so out of the week there is 3 weekend days.

i hope this helps :)

6 0
3 years ago
Please help! 15 points!
MA_775_DIABLO [31]

Answers:

(a) Area: 2108 in²  Perimeter: 192 in

(b)  Area

(c) perimeter

Step-by-step explanation:

To find the area, you do 34 × 62

To find the perimeter you do 34 + 34 + 62 + 62

7 0
3 years ago
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Please answer all or any of the following:-
Nesterboy [21]

Answer:

a) answer is -56,186

b)answer is 1,226

c)answer is -2,953.76

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1 year ago
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A line passes through the point (-6,4) and has a slope of 5/2
matrenka [14]
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6 0
2 years ago
The time to fly between New York City and Chicago is uniformly distributed with a minimum of 120 minutes and a maximum of 150 mi
lara [203]

Answer:

a) 33.33%)

b) 135 minutes

c) 8.66 min

d) 50%

Step-by-step explanation:

a) the probability for a uniform distribution is

P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values

therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)

P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)

b) the mean (expected value) for a uniform probability distribution is

E(X) = (c+d)/2 = (120+150)/2 = 135 minutes

c)  the standard deviation for a uniform probability distribution is

σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²

σ = √75 min² = 8.66 min

b) following the same procedure as in a)

P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)

4 0
3 years ago
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