All you have to do is multiply and add. 63 * 100 = 6,300. 5 * 10 = 5. 2 x 1 = 2. 6,300 + 50 + 2 = 6,352.
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We got the value of by solving the given equations and by reduction method.
<h2>
What is reduction method?</h2>
The reduction or elimination approach includes using arithmetic operations between equations to produce equivalent equations with fewer unknowns that are simpler to analyze and evaluate.
Given equations are
.........(1)
...........(2)
We need to find the value of
Simplifying the given equation (2) and we get
................(3)
Now, substitute the equation (3) in equation (1) and we get
Substitute the value of x in equation (3), we get
Now adding the values of x and y, we get
Therefore, the value of .
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Answer:
C.
Step-by-step explanation:
So there are 20 kids with brown hair and this represents 80% of the class total.
So this means 20=.8n since we don't know the total number of kids.
20=.8n
Divide both sides by .8
25=n
So 25 is the total number of kids.
C. is the answer
You could also setup this equation given that 80% is 80/100:
[tex]\frac{20}{\text{ total }}=\frac{80}{100}
To figure out what that total is there you can divide top and bottom of the fraction on right hand side by 4 which gives you the 20 on top and the 25 on bottom.
For word problems, assign variables so you can express them into equations. For this problem, the unknown is the number of each animals. Let's assign x to the number of cows and y to the number of chickens. It is mentioned that there are a total of 28 animals. Therefore, we can formulate the first independent equation to be
x + y = 28 ---> eqn 1
Next, we know that the total number of legs are 74. Since each cow has 4 legs and each chicken has 2 legs, the second independent equation we could formulate is:
4x + 2y = 74 ---> eqn 2
Now, we have a system of linear equations. There are two unknowns and two independent equations. Thus, the system is solvable. Let's use the method of substituting to solve this. Rearrange eqn 1 such that x is a function of y. Let's denote this as eqn 1'.
x = 28 - y ---> eqn 1'
Substitute eqn 1' to eqn 2:
4(28 - y) + 2y = 74
112 - 4y + 2y = 74
-2y = 74 - 112
-2y = -38
y = -38/-2
y = 19
Therefore, there are 19 chickens. Now, we use y=19 to substitute to eqn 1:
x + 19 = 28
x = 28 - 19
x = 9
Therefore, there are 9 cows.
Answer:
A consumer pays $5 more per camera.
Step-by-step explanation:
Let the cost of manufacture of disposable camera in dollars be
Government taxes imposed on camera = $1.00 per camera
Cost of camera after taxes in dollars
Wholesale prices raised by manufacturer = $2.00 per camera
Wholesale price of camera in dollars per camera
Retail prices raised raised by retailer = $2.00 per camera
Retail price of camera in dollars per camera
Difference in prices of manufacture and retail price per camera in dollars
⇒
⇒
Thus, a consumer pays $5 more per camera.