The answer is simply C.$2.50
Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
Answer:
the zero is at 4 (option 1)
and the minimum is -1 (option 2)
Step-by-step explanation:
the zero is at 4 (option 1)
and the minimum is -1 (option 2)
Paralalell means that is has the same slope
y=mx+b
m=slope
y=-1x-2
slope=-1
the equation of a line that passes through the point (x1,y1) and has a slope of m is y-y1=m(x-x1)
given
(2,-2) and slope is -1
y-(-2)=-1(x-2)
y+2=-x+2
minus 2
y=-x
answer is y=-x
Use the Pythagorean Theorem
RP^2 = 5.3^2 + 3^2
RP^2 =
<span>
<span>
<span>
28.09
</span>
</span>
</span>
+ 9
RP^2 =
37.09
RP =
<span>
<span>
<span>
6.0901559914
</span>
</span>
</span>
So, the answer is 6.1
