1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*

=

(

)
plss take a pic of your quistion
Step-by-step explanation:
I cant understand plss
Given:
Total number of senior students = 600
60% went on the senior trip.
One room was reserved for every 4 students.
To find:
The total number of reserved rooms.
Solution:
60% went on the senior trip from total 600 students. So, number of students who went on tripe is

Now, one room was reserved for every 4 students. So,



Therefore, the required number of reserved rooms were 90.
<span>7800nm + 95pm = (7800x 10^-9) + (95x10^-12) = 7.800095</span><span>x10^-6=</span><span>7.800095mm
</span>
2500nm - 7pm = (2500x 10^-9) + (7x10^-12) = 2.50007x10^-6 = 2.50007mm
(65x10^4m) x (4.5x10^-6s-1) = clarify this question
(24x10^5m) / (2x10^-8s) = clarify this question