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Vinvika [58]
3 years ago
9

In the given figure, identify which of the line segments is longer than XY. Question 15 options: A) TU B) PQ C) VW D) RS

Mathematics
1 answer:
dalvyx [7]3 years ago
7 0

Answer:

A. T, U

Step-by-step explanation:

T and U are stretched across the paper. the others seem a bit close or smaller to the size of X and Y, but when you look at T and U they seem longer than X an Y

Hope this helps!!!  :)

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I need help please...
telo118 [61]
The answer is b
Area=[pi]r2
= [pi](12 in)2
=452.16 in2
7 0
3 years ago
How many batches of ravioli can I make , from 1 gallon at $1.80 that requires 24 ounces
Olin [163]

Answer:

5

Step-by-step explanation:

You can make 5 batches because theres 128 ounces in one gallon so youd divide 128 by 4 and get 5.333 etc. Then youd round to the nearest whole number.

6 0
3 years ago
The area of a baseball field bounded by home plate, first base, second base, and third base is a square. If a player at first ba
slega [8]

Answer:

120ft

Step-by-step explanation:

If the bases are 120ft apart from each other you would have to find the distance of going from first to second then to third. Then you divide it in half because you arent going around the diamond, you are cutting right through it.

8 0
3 years ago
Read 2 more answers
What basic trigonometric identity would you use to verify that (sin2x + cos2x)/cosx=secx
Oksana_A [137]

Answer:

Step-by-step explanation:

sin(2x) = 2 sin(x) cos(x) cos(2x) = cos2(x) – sin2(x) = 1 – 2 sin2(x) = 2 cos2(x) – 1. Now I am not sure if this is right but I remember another similar formula. Here is the correct formula cot x = cos x / sin x

2 ) ( sin² x + cos² x ) / cos x = sec x

1/cos x = sec x

sec x = sec x

cos² x + sin² x = 1

7 0
3 years ago
Read 2 more answers
Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

So that;

n = \frac{ 1.8083 * 10^{4} }{2}

   = 0.90415 x 10^{4}

n =  0.90415 x 10^{4} Km

Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

                     = 326994889

Surface area = 3.2700 x 10^{8} km^{2}

Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

4 0
3 years ago
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