The circumference of the circle shown below is 42 centimeters. Which

Mathematics

2 answers:

Ede4ka [16]3 years ago

3 0

Answer:

It is answer B (125 / 360) * 42

Step-by-step explanation:

skad [1K]3 years ago

3 0

Answer: B . $\frac{125}{360}$ . 42

Step-by-step explanation:

AB is an arc , the formula for calculating the length of an arc is given as

L = Ф/360 X 2πr

where Ф is the angle subtended by the arc , 2πr is the circumference of the circle.

Substituting the given values into the formula , we have

L = 125/360 x 42

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Given: a||b, m∠ 6=128° Find: m∠1, m∠3

goldfiish [28.3K]

Answer:

m∠1 = 52°

m∠3 = 52°

Step-by-step explanation:

Step 1:

Since b is a straight line and is transversed by line m and we are given m∠6 = 128°, we can find m∠5, which is 180 - m∠6, giving us 52° for ∠5.

Step 2:

Because a and b are parallel, m∠5 and the m∠1 are the same, so we have m∠1 = 52° as one of our answers needed

Step 3: Because ∠3 is vertical to ∠1, we can use the vertical angles theory and say that m∠1 is equal to m∠3. Therefore, m∠3 = 52°

5 0

3 years ago

A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. The rang

VARVARA [1.3K]

Answer:

$\theta=24.4^\circ$

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and v = 85 ft/s, we can substitute these values from the equation written, and we will have $\theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}$ , and from now on we have just to use a calculator, obtaining $\theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ$