What is the period, in seconds, of the simple harmonic motion described by the equation x = 3sin(4πt)?
2 answers:
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Move constant to the right-hand side and change its sign
2x^2 + 8 = -2 + 7
-2 + 7 = 5
Divide both sides of the equation by
x^2 + 4x = 5/2
Add (4/2^2) to both sides of the equation
x^2 + 4x + (4/2)^2 = 5/2 + (4/2)^2
factor the expression
(x + 4/2)^2 = 13/2
reduce the fraction by 2
(x + 2)^2 = 13/2
now solve equation for x
2x^2 + 8 = -2 + 7
-2 + 7 = 5
Divide both sides of the equation by
x^2 + 4x = 5/2
Add (4/2^2) to both sides of the equation
x^2 + 4x + (4/2)^2 = 5/2 + (4/2)^2
factor the expression
(x + 4/2)^2 = 13/2
reduce the fraction by 2
(x + 2)^2 = 13/2
now solve equation for x