Answer:
For this case, the first thing we must do is define variables:
x: number of hammers
y: number of wrenches
We write the system of inequations:
10x + 6y <= 120
x + y> = 14
Step-by-step explanation:
Answer:
A) The fraction of sum of money did each child receive is
B) The sum of money did Jeff have $ 3200
Step-by-step explanation:
Given as :
Let The sum of money did Jeff have = $ x
The fraction of money did Jeff's wife get =
of $ x
The remaining money Jeff will have = $ x -
of $ x
I.e The remaining money Jeff will have =
=
A ) The remaining amount of money is divided equally among 4 children
So, The fraction of sum of money did each child receive = 
I.e The fraction of sum of money did each child receive =
B ) If each child will receive $ 600
∴,
= $ 600
Or, 3 x = $ 600 × 16
Or, 3 x = $ 9600
∴ x = 
I.e x = $ 3200
So, The sum of money did Jeff have $ 3200
Hence ,
A) The fraction of sum of money did each child receive is
B) The sum of money did Jeff have $ 3200 Answer
Answer:
5
Step-by-step explanation:
40÷[20-4*(7-4)]
Start with the inner most parentheses
40÷[20-4*(3)]
Then the brackets, multiply first
40÷[20-12]
Then subtract
40÷[8]
We are now left with the division
5
Answer:
9/15=3/5
so 3/5 is equivalent fraction of the 9/15