This is the concept of applications of polynomial equations. Given that the height of the ball is modeled by the function:
h(t)=16t^2-64t
the maximum height will be calculated as follows;
h(t)=16t(t-4)
therefore:
t=0 or t=4
h(4)=-64(4)+16(4^2)
=0
Answer:
0.9
m
−
12
Note:
Since there is no y value m can not be determine. Therefore finding the sum here can not be determined so instead you can try simplifying
Answer:
16
Step-by-step explanation:
Because the number is closer to 16, it can be rounded off to that. 15 31/40 is the same as 15.78. When the decimal is over .50 it is rounded up to the next whole number, but when it is under .50 it si rounded down to the nearest whole number. ex. since this one is over the .50, it's rounded up, but if it were 15.36 then it would be rounded down to 15. hope this helps :D
Answer:
<u>5/4</u>
Step-by-step explanation:
Given :
- tanθ = 3/4 = opposite/adjacent
Finding the missing side :
- The hypotenuse must be found
- √3² + 4²
- √25
- 5
Taking the sec ratio :
- secθ = hypotenuse/opposite
- secθ = <u>5/4</u>
Answer:Rigid transformations preserve segment lengths and angle measures.
A rigid transformation, or a combination of rigid transformations, will produce congruent figures.
In proving SAS, we started with two triangles that had a pair of congruent corresponding sides and congruent corresponding included angles.
We mapped one triangle onto the other by a translation, followed by a rotation, followed by a reflection, to show that the triangles are congruent.
Step-by-step explanation:
Sample Response: Rigid transformations preserve segment lengths and angle measures. If you can find a rigid transformation, or a combination of rigid transformations, to map one triangle onto the other, then the triangles are congruent. To prove SAS, we started with two distinct triangles that had a pair of congruent corresponding sides and a congruent corresponding included angle. Then we performed a translation, followed by a rotation, followed by a reflection, to map one triangle onto the other, proving the SAS congruence theorem.
