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AlekseyPX
3 years ago
12

A motorboat sets out in the direction N 77 degrees 48 minutes E. THe speed of the boat in still water is 31.7 mph. If the curren

t is flowing directly south, and the actual direction of the motorboat is due east, find the speed of the current and the actual speed of the motorboat
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
5 0

Answer:

7.09 mph

30.87 mph

Step-by-step explanation:

We are given that

\theta=77^{\circ} 48'=77+\frac{48}{60}=77.8^{\circ}

1 degree=60 minute

The speed of boat in still water=v=31.7mph

We have to find the speed of the current and the actual speed of the motorboat.

\theta'=90-77.8=`2.92^{\circ}

Speed of the current=vsin\theta'

Speed of the current=31.7sin12.92=7.09 mph

Actual speed of the motorboat=vcos\theta'=31.7cos12.92=30.87mph

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How do the values in Pascal’s triangle connect to the coefficients?
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Each row in Pascal's triangle is a listing of the values of nCk = n!/(k!(n-k)!) for some fixed n and k in the range 0 to n. nCk is <em>the number of combinations of n things taken k at a time</em>.

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