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Ilia_Sergeevich [38]
3 years ago
5

a polynomial has been factored below, but some constants are missing. 2x^3-2x^2-24x=ax(x+b)(x+c) what are the missing values of

a,b, and c?

Mathematics
2 answers:
otez555 [7]3 years ago
6 0
Hello here is a soluion : 

Eduardwww [97]3 years ago
4 0

Answer:

a=2, b= -4, c=3

Step-by-step explanation:

2x^3-2x^2-24x=ax(x+b)(x+c)

Find out the constants a,b and c

LEts factor the given expression

2x^3-2x^2-24x

GCF is 2x

2x(x^2-x-12)

Factor out x^2-x-12

Product is -12 and sum is -1

-4 times 3 is -12

-4 plus 3 is -1

x^2-x-12 = (x-4)(x+3)

2x(x^2-x-12)

2x(x-4)(x+3)

The value of 'a' is 2

'b' is -4 and 'c' is 3

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Complete question:

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Step-by-step explanation:

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Let's substitute T + 11 for T1 in equation 2, we have:

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