Assuming that <span>4^2-6(2^x)-16=0 is correct, we can rearrange it as:
</span><span>-6(2^x) + 4^2 - 16=0
Are you sure it's not </span>6(2^x) + 4^2 - 16=0 ?
If 6(2^x) + 4^2 - 16=0 is correct, then
6(2^x) + 4^2 - 16=16 - 16 = 0, that is, 6(2^x) = 0. Then x = 0 (answer)
16 - x = 4
16 - 12 = 4
x = 12
Hey.
acc'g to the conditions :
Let Catherine has x
and James has 5 + 3x
Then,

Hence
• Catherine has = x = $9,
• and James has = 5 +3x = 5 + 3(9) = $32
Thanks.
For this case we have to:
x: Represents the unknown number
y: Represents the exponent of base 10
So, considering a system of equations we have:

From the first equation we have:

Substituting in the second equation:

We choose the positive value:

So, the number is 0.4.
So:

Thus, the exponent is 5.
Answer:
Yara use 0.4 and