Solve each inequality. p + 5 < 10 A. p < –15 B. p < 5 C. p < 15 D. p <

5
2 = 32

Exponents are like a simplified or easier version of multiplying
2*2*2*2*2

People use exponents in real life. For an example, they use it for finding cubic feet ,square feet, or area of something or an object.

Sorry if I am bad at explaining this or if I confused you

7 0

3 years ago

If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.

Bingel [31]

Given:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

Probability of getting two queens and two kings:

The number of ways of getting two queens is $4C_2$

The number of ways of getting two kings is $4C_2$

Total number of cases is $52C_4$

The probability of getting two queens and two kings is given by

$\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}$

Substituting the values, we get;

$probability=\frac{4C_2 \cdot 4C_2}{52C_4}$

Simplifying, we get;

$probability=\frac{6 (6)}{270725}$

$probability=\frac{36}{270725}$

$probability=0.000133$

Thus, the probability of getting two queens and two kings is 0.000133

7 0

3 years ago

Evaluate: 6-(2/3)^2 A. 17/3 B. 52/3 C. 49/9 D. 50/9

Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

....................................................................................................................................

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations! :)

$\dag\textsf{Acronym \: PEMDAS}$

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is $\mathsf{6-(\cfrac{2}{3})^2}$

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain $\mathsf{6-\cfrac{4}{9}}$ .

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: $\mathrm{\cfrac{6}{1}-\cfrac{4}{9}}$ . Now let's multiply the denominator and the numerator of the first fraction times 9: $\mathrm{\cfrac{54}{9}-\cfrac{4}{9}}$ .

See, now the fractions have the same denominator. All we should do now is subtract the numerators: $\mathrm{\cfrac{50}{9}}$ .

∴, the answer is Option D.

Hope this helped you out, ask in comments if any queries arise.

Best Wishes!

$\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star$

$\underline{\rule{300}{5}}$

5 0

2 years ago

Read 2 more answers

Solve each inequality. p + 5 < 10 A. p < –15 B. p < 5 C. p < 15 D. p < –5