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lapo4ka [179]
3 years ago
6

Solve each inequality. p + 5 < 10 A. p < –15 B. p < 5 C. p < 15 D. p < –5

Mathematics
1 answer:
EastWind [94]3 years ago
5 0

Answer:

B) p<5

Step-by-step explanation:

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PLEASE HELP!!!!!!!!!!
erik [133]

Answer: D

Step-by-step explanation:

7 0
2 years ago
Solve for x in the equation x squared + 2 x + 1 = 17.
Papessa [141]

Answer:

x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\

Step-by-step explanation:

given equation

x^2 +2x +1 = 17

subtracting 17 from both sides

x^2 +2x +1 = 17\\x^2 +2x +1 -17= 17-17\\x^2 +2x - 16 = 0\\

the solution for quadratic equation

ax^2 + bx + c = 0 is given by

x = x = -b + \sqrt{b^2 - 4ac} /2a \\\\and \ \\-b - \sqrt{b^2 - 4ac} /2a

________________________________

in our problem

a = 1

b = 2

c = -16

x =( -2 + \sqrt{2^2 - 4*1*-16}) /2*1 \\x =( -2 + \sqrt{4  + 64}) /2\\x =( -2 + \sqrt{68} )/2\\x = ( -2 + \sqrt{4*17} )/2\\x =  ( -2 + 2\sqrt{17} )/2\\x = - 1 + \sqrt{17}\\and\\\\x = - 1 - \sqrt{17}\\

thus value of x is

x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\

3 0
2 years ago
you have a large container of olive oil. You have used 22 1/2 quarts of oil. Twenty- five percent of the oil remain. How many qu
Alex Ar [27]
Answer:

7.5 quarts of olive oil remain.

Explanation:

Let

q = quarts of olive oil remain

<span>25%</span> of olive oil remains means that <span>75%</span> has been used.

22<span>12</span> quarts = 22.5 quarts used

<span><span>22.5.75</span>=<span>q.25</span></span>

Multiply both sides by .25 to isolate q.

<span><span>22.5.75</span><span>(.25)</span>=<span>q.25</span><span>(.25)</span></span>

<span><span>5.625.75</span>=q</span>

<span>7.5=<span>q</span></span>

3 0
3 years ago
How much larger is 400 than 40?
dlinn [17]
360

400 - 40 = 360

Did I help? Say thanks on my profile!
8 0
3 years ago
Read 2 more answers
Write in simplest form:<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti
Charra [1.4K]

Answer:

2a^3b^2\sqrt[3]{3a}

Step-by-step explanation:

Use the following rules for exponents:

a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

8*3=24\\\\2^3=8

Insert:

\sqrt[3]{2^3*3a^{10}b^6}

Now split the exponents. Split 10 into as many 3's as possible:

10=3+3+3+1

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}

Split 6 into as many 3's as possible:

6=3+3

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}

Simplify:

2a^3b^2\sqrt[3]{3a}

:Done

6 0
2 years ago
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