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3 years ago

What is the measure for the following ∠? m∠AOX

Mathematics

1 answer:

dangina [55]3 years ago

6 0

Answer:the answer is 40

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Helpppppp :((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((9999

Anni [7]

Answer is C and E.

All of the other ones don't follow order of operations properly.

4 0

3 years ago

I'm really confused on this one please answer !!!!!!!

Sedbober [7]

The formula for finding the area of a rug: $A = s^2$

Plugging in the values we know, we can solve for s.

$79 = s^2$

Take the square root of both sides.

$\sqrt{79} = s$

$\sqrt{79}$ is approximately equal to 8.89

So, 8.89 feet is the answer.

4 0

3 years ago

Identify the graph of the equation. What is the angle of rotation for the equation?<br><br>xy=-2.5

Maurinko [17]

Answer:

It is B. hyperbola, 45 degrees.

SteIt is p-by-step explanation:

If we rotate the standard form x^2 - y^2 = 1 through 45 degrees we get xy = 1/2.

xy = -2.5 comes from x^2 - y^2 = -5 being rotated 45 degrees.

3 0

4 years ago

Read 2 more answers

Pls help is it A. B. C. D.

Ivenika [448]

Answer:

Step-by-step explanation:

Hope I was able to help!! :)

7 0

3 years ago

Find the value of k if the distance between (2,k) and (6,7) is 4√2 unit

andreyandreev [35.5K]

Answer:

k = 3

Step-by-step explanation:

We have the distance formula: $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ . We can plug in $4\sqrt{2}$ = d, x2 = 6, x1=2, y2 = 7, y1 = k.

Then, we can solve the question using some algebra to find that k = 3.

Edit: Here is a step by step:

$4\sqrt{2} = \sqrt{(6-2)^2 + (7-k)^2}\\$

$(4\sqrt{2})^2 = (6-2)^2 + (7-k)^2$

$32 = (4)^2 + (7-k)^2$

$32 = 16 + (7-k)^2$

$32 - 16 = (7-k)^2$

$16 = (7-k)^2$

$\sqrt{16} = (7-k)$

$4 = 7-k$

$k = 3$

4 0

3 years ago