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Licemer1 [7]
3 years ago
7

Find the greatest of four consecutive integers if when the least integer is decreased by twice the greatest integer the result i

s 14.
Mathematics
1 answer:
AlekseyPX3 years ago
5 0
Let n = 1st integer (least)
      n + 1 = 2nd integer
      n + 2 = 3rd integer
      n + 3 = 3rd integer (greatest)

n - 2(n + 3) = 14
n - 2n - 6 = 14
-n - 6 = 14
-n - 6 + 6  = 14 + 6
-n = 20
n = -20
 n + 1 = -19
 n + 2 = -18
 n + 3 = -17
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Which of the following statements is true of the diagram below?
Nata [24]

Answer:

D

Step-by-step explanation:

tan=adjacent side/opposite side

sin=adjacent side/hypotenuse

cos=opposite side/hypotenuse

knowing this:

cos P=8/17, so a is false

tan Q=8/15, so b is false

sin P=15/17, so c is false

cos Q= 15/17, so only d is true

5 0
3 years ago
PleAsee help me solve this
torisob [31]

Answer:

1st blank: 1

2nd blank: -3

Step-by-step explanation:

Y_{2} - Y_{1} / X_{2} - X_{1}

1 - 2 / 4 - 5

-1/-1

slope = 1

1 = 4 + b

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hope this helps :)

4 0
3 years ago
What times what equals -42
madam [21]

Answer:

-7 times 6 equals -42

Step-by-step explanation:

3 0
3 years ago
Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposi
Zanzabum

1. N is a midpoint of the segment KL, then N has coordinates

\left(\dfrac{x_K+x_L}{2},\dfrac{y_K+y_L}{2} \right) =\left(\dfrac{0+2a}{2},\dfrac{2b+0}{2} \right) =(a,b).

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

A_{KMN}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2b\cdot a=ab.

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

A_{MNL}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2a\cdot b=ab.

4. Comparing the expressions for the areas you have that the area A_{KMN} is equal to the area A_{MNL}. This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

6 0
3 years ago
Read 2 more answers
A survey conducted by the Consumer Reports National Research Center reported, among other things, that women spend an average of
Nookie1986 [14]

Answer:

(a) The probability that a randomly selected woman shop exactly two hours online is 0.217.

(b) The probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c) The probability that a randomly selected woman shop less than 5 hours online is 0.9922.

Step-by-step explanation:

Let <em>X</em> = time spent per week shopping online.

It is provided that the random variable <em>X</em> follows a Poisson distribution.

The probability function of a Poisson distribution is:

P (X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0,1,2,...

The average time spent per week shopping online is, <em>λ </em>= 1.2.

(a)

Compute the probability that a randomly selected woman shop exactly two hours online over a one-week period as follows:

P (X=2)=\frac{e^{1.2}(1.2)^{2}}{2!} =0.21686\approx0.217

Thus, the probability that a randomly selected woman shop exactly two hours online is 0.217.

(b)

Compute the probability that a randomly selected woman shop 4 or more hours online over a one-week period as follows:

P (X ≥ 4) = 1 - P (X < 4)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

              =1-\frac{e^{1.2}(1.2)^{0}}{0!}-\frac{e^{1.2}(1.2)^{1}}{1!}-\frac{e^{1.2}(1.2)^{2}}{2!}-\frac{e^{1.2}(1.2)^{2}}{3!}\\=1-0.3012-0.3614-0.2169-0.0867\\=0.0338

Thus, the probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c)

Compute the probability that a randomly selected woman shop less than 5 hours online over a one-week period as follows:

P (X < 5) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

              =\frac{e^{1.2}(1.2)^{0}}{0!}+\frac{e^{1.2}(1.2)^{1}}{1!}+\frac{e^{1.2}(1.2)^{2}}{2!}+\frac{e^{1.2}(1.2)^{3}}{3!}+\frac{e^{1.2}(1.2)^{4}}{4!}\\=0.3012+0.3614+0.2169+0.0867+0.0260\\=0.9922

Thus, the probability that a randomly selected woman shop less than 5 hours online is 0.9922.

8 0
4 years ago
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