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vesna_86 [32]
3 years ago
7

The grace period is the _____. maximum amount of money you can charge on the credit card time before the credit card company sta

rts charging late fees least amount of money that must be paid at the end of a month period of time before the credit card company starts charging interest
Mathematics
2 answers:
Lisa [10]3 years ago
6 0

Answer:

Period of time before the credit card company starts charging interest

Step-by-step explanation:

We know that,

'Grace Period' is the period after the deadline, during which a late fee or other action, that would have been taken on failing to meet the deadline, is waived off with the condition that the obligation is completed during the grace period.

So, according to the options, we get that,

The grace period is 'the period of time before the credit card company starts charging interest'.

GenaCL600 [577]3 years ago
5 0
I'll just clarify the choices you gave:
-<span>maximum amount of money you can charge on the credit card time before the credit card company starts charging late fees
</span>-l<span>east amount of money that must be paid at the end of a month
</span>-<span>period of time before the credit card company starts charging interest

If these are correct, then the answer is 'period of time before the credit card company starts charging interest'. </span>
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A pack of pencils, p, costs $1.99. A school buys $129.35 worth of pencils.
rosijanka [135]

Answer:

p=65. the value of p is the amount of pencils packs.

Step-by-step explanation:

1.99p=129.35

129.35/1.99=65

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(Will Mark Brainliest!!!)Choose the point-slope form of the equation below that represents the line that passes through the poin
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Answer:

b

Step-by-step explanation:

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3 years ago
Find the state income tax deducted: gross pay of $978, state income tax 5%.
Helga [31]
$48.90

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Read 2 more answers
An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand
Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

b) We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

Part b

We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

4 0
3 years ago
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