Question

A silo is comprised of a cylindrical body and a hemispherical dome on top. If the height of the cylinder is 35 feet and the radius of the dome is 9 feet, what is the volume of the silo to the nearest cubic foot?

Answer 1

Answer:

10433 cubic feet.

Step-by-step explanation:

First, it would be helpful to find the volume of each part of the silo.

The cylinder has a height of 35 feet and a circular base with a radius of 9 feet. The volume of a cylinder is pi*(r^2)*h, in this case,  pi*(9^2)*35. The answer is approximately 8906.415 cubic feet.  

Now, find the volume of the dome. The dome has a radius of 9 feet. The dome is a sphere, cut in half. So the formula for finding the volume of the dome would be (4/3)*pi*(r^3)*(1/2), in this case, (4/3)*pi*(9^3)*(1/2).  The answer would be approximately 1526.814 cubic feet.

Now, add the two volumes together.  8906.415+1526.814=10433.229 .

Now round to the nearest whole number.