Y=2x^3 is nonlinear, since it's a cube equation. y=x+5 is linear, because it's a line with y intercept (0,-5) and slope 1. y=\sqrt(x-5) is nonlinear, because it's a quadratic equation when reversing x and y. 5x+5y=25 is equal to x+y=5 ot y=-x+5, which is also linear. y=x^2/2 is a quadratic equation, so it's nonlinear.
The zero of a function is the x-value at which the function value is zero. That is, the value of the function that intersects the x-axis. From the picture, the zero is -5
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Answer:
(1,2)
Step-by-step explanation:
y = 2x. y = -x+3
Set the two equations equal
2x = -x+3
Add x to each side
2x+x = -x+x+3
3x = 3
Divide by 3
3x/3 = 3/3
x = 1
Now find y
y =2x = 2(1) = 2
(1,2)
